Answer:
0.045454544.....
Step-by-step explanation:
not sure hope it will be true
Answer:
Speed of boat in still water = 64 km/hr
Speed of the current = 11 km/hr
Step-by-step explanation:
Let the speed of motorboat in still water = x km/hr
Let the speed of current = y km/hr
Motorboat travels 371 km in 7 hours going upstream.
Speed of motorboat while going upstream = speed of motorboat in still water - speed of current = (x-y)
=> ![\[x-y = \frac{371}{7}\]](https://tex.z-dn.net/?f=%5C%5Bx-y%20%3D%20%5Cfrac%7B371%7D%7B7%7D%5C%5D)
=>
------------------------------(1)
Motorboat travels 525 km in 7 hours going downstream.
Speed of motorboat while going downstream = speed of motorboat in still water + speed of current = (x+y)
=> ![\[x+y = \frac{525}{7}\]](https://tex.z-dn.net/?f=%5C%5Bx%2By%20%3D%20%5Cfrac%7B525%7D%7B7%7D%5C%5D)
=>
-----------------------------(2)
Solving for x and y from (1) and (2):
Adding (1) and (2):
2x = 128
=> x = 64
Substituting the value of x in (1), y = 11
19/8 is the improper fraction of 2 3/8.
Answer:
The correct answer is 5 years i.e. 2008.
Step-by-step explanation:
Price of the automobile in 2003 is $32000.
Depreciation per year is given by $1740.
Therefore let the car value is depreciated for t number of years.
Value depreciated for t years is given by $ (1740t).
The final value of the car after t years is given to be $23300.
Thus the equation is given by 32000 - 1740t = 23300.
⇒ 1740t = 32000 - 23300
⇒ 1740t = 8700
⇒ t = 5
Thus after 5 years the value of the car is $23300.
Thus in 2008 the depreciated price of the car would be $23300.
If you mean y=2x+12 then the line crosses at positive 12