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3 years ago

SOMEONE HELP ME PLS, I'M stuck on this one since yesterday!

1 answer:

7 0

$\bf \begin{cases}
F = \{(0, 1), (\stackrel{x}{2}, \stackrel{y}{4}), (4, 6), (6, 8)\} & F(\stackrel{x}{2})=\stackrel{y}{4}
\\\\\\
G = \{(\stackrel{x}{2}, \stackrel{y}{5}), (4, 7), (5, 8), (6, 9), (7, 5)\} \qquad & G(\stackrel{x}{2})=\stackrel{y}{5}
\end{cases} 
\\\\\\
(F\cdot G)(2)\implies F(2)\cdot G(2)\implies 4\cdot 5\implies 20$

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Step-by-step explanation:

1. We already know he has $40.

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3 years ago

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3 years ago

Litter such as leaves falls to the forest floor, where the action of insects and bacteria initiates the decay process. Let A be

Travka [436]

Answer:

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Step-by-step explanation:

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Since litter decays at a constant proportional rate of k per year, the total amount of litter decay per square meter per year is A × k = Ak = out flow

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Separating the variables, we have

dA/(L - Ak) = dt

Integrating, we have

∫-kdA/-k(L - Ak) = ∫dt

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1/k㏑(L - Ak) = t + C

㏑(L - Ak) = kt + kC

㏑(L - Ak) = kt + C' (C' = kC)

taking exponents of both sides, we have

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When t = 0, A(0) = 0 (since the forest floor is initially clear)

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So, D = R - A =

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when t = 0(at initial time), the initial value of D =

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3 years ago

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2 years ago