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Umnica [9.8K]
3 years ago
6

SOMEONE HELP ME PLS, I'M stuck on this one since yesterday!

Mathematics
1 answer:
AfilCa [17]3 years ago
7 0
\bf \begin{cases}
F = \{(0, 1), (\stackrel{x}{2}, \stackrel{y}{4}), (4, 6), (6, 8)\} &  F(\stackrel{x}{2})=\stackrel{y}{4}
\\\\\\
G = \{(\stackrel{x}{2}, \stackrel{y}{5}), (4, 7), (5, 8), (6, 9), (7, 5)\} \qquad & G(\stackrel{x}{2})=\stackrel{y}{5}
\end{cases} 
\\\\\\
(F\cdot G)(2)\implies F(2)\cdot G(2)\implies 4\cdot 5\implies 20
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Quadrilateral LMNO has diagonals that intersect at point P. If LP=NP, MP = y + 25, and OP = 5y + 29, find the length of MO such
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I saw the image of this problem.

For the quadrilateral to be parallelogram, MP = PO

MP = y + 25
PO = 5y + 29

y + 25 = 5y + 29
y - 5y = 29 - 25
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y = 4/-4
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MO = -1 + 25 + 5(-1) + 29
MO = -1 + 25 - 5 + 29
MO = -6 + 54
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