Question

Calculate solute of a 0.1M NaCl solution at 25 degrees Celsius. If the concentration of NaCl inside the plant cell is 0.15M, which way will the water diffuse if the cell is placed into the 0.1M NaCl solution?

Answer 1

 The solute potential is expressed in the formula P= – iCRT, where i = the ionization constant, C = the molar concentration , R = the pressure constant (R = 0.0831 liter * bars/mole * K), and T = the temperature in K (273 + °C). At atmospheric pressure and 25°C has an osmotic potential - A 0.15 M NaCl solution contains 2 ions, Na+ and Cl- (where sucrose stays as one particle); therefore i = 2, and the water potential = -7.4 bars. 
Water will move into the cell by osmosis from 0.1 to 0.15.

Answer 2

Answer:

The correct answer is -7.429 bars.

Explanation:

The solute potential inside the cell is calculated by the formula = -iCRT

Here, i refers to the number of ions, C refers to the concentration of solute, R refers to the gas constant, and T is the temperature (K)

The concentration within the cell of the plant is 0.15 M for NaCl, i = 2, R = 0.0831 and T = 298 K or 25 degree C.  

Solute potential = - (2 * 0.15 * 0.0831 * 298) = -7.429 bar