Answer:
x = 500 yd
y = 250 yd
A(max) = 125000 yd²
Step-by-step explanation:
Let´s call x the side parallel to the stream ( only one side to be fenced )
y the other side of the rectangular area
Then the perimeter of the rectangle is p = 2*x + 2* y ( but only 1 x will be fenced)
p = x + 2*y
1000 = x + 2 * y ⇒ y = (1000 - x )/ 2
And A(r) = x * y
Are as fuction of x
A(x) = x * ( 1000 - x ) / 2
A(x) = 1000*x / 2 - x² / 2
A´(x) = 500 - 2*x/2
A´(x) = 0 500 - x = 0
x = 500 yd
To find out if this value will bring function A to a maximum value we get the second derivative
C´´(x) = -1 C´´(x) < 0 then efectevly we got a maximum at x = 500
The side y = ( 1000 - x ) / 2
y = 500/ 2
y = 250 yd
A(max) = 250 * 500
A(max) = 125000 yd²
Answer:
5000-1250x
Step-by-step explanation:
All you need to do is find the amount of money you get paid a month and use variable x to represent the months and then subtract that from the money you need to pay off.
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He circumference of a circle<span> is equal to the diameter times pi. So, let's look at </span>what happens<span> if you double the </span>radius<span> of a </span>circle<span> -- say from 2 to 4. The area will go from 12.56 to 50.24. This means that it has </span>quadrupled<span>.</span>
