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nirvana33 [79]
3 years ago
14

What is the answer to this problem?

Mathematics
1 answer:
salantis [7]3 years ago
7 0
We must first Isolate the Variable by removing factors that don't contain the variable: 

2(x + 7) < 12
2x + 14 < 12
2x + 14 - 14 < 12 - 14
2x < -2 
2x / 2 < -2/2
x < -1

Hope this helps! 



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Can somebody help me on 23 and 24, it’s geometry
alexdok [17]

Answer:

  23.  x = 4; DE = 44

  24.  x = 25; DS = 28

Step-by-step explanation:

23. Point S is the midpoint of DE, so ...

  DS = SE

  3x +10 = 6x -2

  12 = 3x . . . . . . . . . add 2-3x

  4 = x . . . . . . . . . . . divide by 3

Then DS has length ...

  DS = 3x +10 = 12 +10 = 22

and DE is twice that length, so ...

  DE = 44

__

24. DS is half the length of DE, so is ...

  DS = DE/2 = 56/2

  DS = 28

Then x can be found from ...

  DS = x +3

  28 -3 = x = 25 . . . . . substitute value for DS

_____

<em>Comment on problem 24</em>

Sometimes it is easier to work parts of a problem out of sequence. Here, finding DS first makes finding x easier.

8 0
3 years ago
Read 2 more answers
The diameter of a circle is 24 feet. What
kupik [55]
<h3>Answer: Circumference is approximately 75.36 feet</h3>

=======================================================

Work Shown:

d = diameter = 24 ft

pi = 3.14 approx

C = circumference of circle

C = pi*d

C = 3.14*24

C = 75.36 feet

3 0
3 years ago
What is the value of x to the nearest tenth?<br> A. 6.0<br> B. 13.4<br> C. 26.8<br> D. 30.0
lilavasa [31]
Use the Pythagorean theorem:

\left(\dfrac{1}{2}x\right)^2+12^2=18^2\\\\\dfrac{1}{4}x^2+144=324\ \ \ |-144\\\\\dfrac{1}{4}x^2=180\ \ \ \ |\cdot4\\\\x^2=720\to x=\sqrt{720}\\\\\boxed{x\approx26.8}
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4 years ago
PLEASE HELP<br><br>divide. (3x-2)(x-4)-(x-4)(6-5x)<br>/(4-x)(8x-1)​
8_murik_8 [283]

Answer:

x = 39/74 - sqrt(1817)/74 or x = 39/74 + sqrt(1817)/74

Step-by-step explanation:

Solve for x:

(x - 4) (3 x - 2) - ((6 - 5 x) (x - 4) (8 x - 1))/(4 - x) = 0

Simplify and substitute y = 4 - x.

(x - 4) (3 x - 2) - ((6 - 5 x) (x - 4) (8 x - 1))/(4 - x) = -434 + 257 (4 - x) - 37 (4 - x)^2

= -37 y^2 + 257 y - 434:

-37 y^2 + 257 y - 434 = 0

Divide both sides by -37:

y^2 - (257 y)/37 + 434/37 = 0

Subtract 434/37 from both sides:

y^2 - (257 y)/37 = -434/37

Add 66049/5476 to both sides:

y^2 - (257 y)/37 + 66049/5476 = 1817/5476

Write the left hand side as a square:

(y - 257/74)^2 = 1817/5476

Take the square root of both sides:

y - 257/74 = sqrt(1817)/74 or y - 257/74 = -sqrt(1817)/74

Add 257/74 to both sides:

y = 257/74 + sqrt(1817)/74 or y - 257/74 = -sqrt(1817)/74

Substitute back for y = 4 - x:

4 - x = 257/74 + sqrt(1817)/74 or y - 257/74 = -sqrt(1817)/74

Subtract 4 from both sides:

-x = sqrt(1817)/74 - 39/74 or y - 257/74 = -sqrt(1817)/74

Multiply both sides by -1:

x = 39/74 - sqrt(1817)/74 or y - 257/74 = -sqrt(1817)/74

Add 257/74 to both sides:

x = 39/74 - sqrt(1817)/74 or y = 257/74 - sqrt(1817)/74

Substitute back for y = 4 - x:

x = 39/74 - sqrt(1817)/74 or 4 - x = 257/74 - sqrt(1817)/74

Subtract 4 from both sides:

x = 39/74 - sqrt(1817)/74 or -x = -39/74 - sqrt(1817)/74

Multiply both sides by -1:

Answer:  x = 39/74 - sqrt(1817)/74 or x = 39/74 + sqrt(1817)/74

7 0
3 years ago
What value of c makes x2+6x+c a perfect square trimonial
DaniilM [7]

Answer:

9

Step-by-step explanation:

To solve this just take b (in this case 6x) divide it by 2 and then square it

which means that c=9

this will factor to (x+3)²

8 0
3 years ago
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