Pythagoras was born about 582 BC Isaac Newton was born in 1643 AD how many years apart were they born?

Mathematics

2 answers:

Dima020 [189]3 years ago

7 0

582 BC + 1643 AD = 1061 <=== number of years apart.

SSSSS [86.1K]3 years ago

3 0

2225 years. Since 582 BC is 582 years away from zero and 1643 is 1643 units away from zero, you add them together. Think of it like a number line.

You might be interested in

If the diagonal path is 750 feet long and the width of the park is 450 feet, what is the length, in the feet, of the park?

disa [49]

Answer:

The length is 600 ft

Step-by-step explanation:

We can use the Pythagorean theorem since we know the diagonal which is the hypotenuse and the width

a^2 + b^2 = c^2

450 ^2 + b^2 = 750^2

b^2 = 750^2 - 450^2

b^2 =562500-202500

b^2 =360000

Taking the square root of each side

sqrt(b^2) = sqrt(360000)

b =600

4 0

3 years ago

Find the roots of h(t) = (139kt)^2 − 69t + 80

Sonbull [250]

Answer:

The positive value of $k$ will result in exactly one real root is approximately 0.028.

Step-by-step explanation:

Let $h(t) = 19321\cdot k^{2}\cdot t^{2}-69\cdot t +80$ , roots are those values of $t$ so that $h(t) = 0$ . That is:

$19321\cdot k^{2}\cdot t^{2}-69\cdot t + 80=0$ (1)

Roots are determined analytically by the Quadratic Formula:

$t = \frac{69\pm \sqrt{4761-6182720\cdot k^{2} }}{38642}$

$t = \frac{69}{38642} \pm \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} }$

The smaller root is $t = \frac{69}{38642} - \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} }$ , and the larger root is $t = \frac{69}{38642} + \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} }$ .

$h(t) = 19321\cdot k^{2}\cdot t^{2}-69\cdot t +80$ has one real root when $\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} = 0$ . Then, we solve the discriminant for $k$ :