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asambeis [7]
3 years ago
13

Solve the absolute value inequality|2x+3|≥|x−7|

Mathematics
1 answer:
amm18123 years ago
3 0

Answer:x\geq 7

Step-by-step explanation:

Given

|2x+3|\geq |x-7|

here we will divide x interval in 3 case

case x

let us take x=-2

|-1| is not greater than |-9|

thus x is not possible

Case     \frac{-3}{2}

Take x=0

|3| is less than |-7|

thus for  \frac{-3}{2} equality is not satisfied

Case 3   x\geq 7

take x=7

|17| is greater than |0|

Thus forx\geq 7 is the required region

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9.55 as a mixed number would be 9 11/20.

9.55 = 9 55/100 = 9 11/20

Hope this helps !

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3 years ago
What are the binomial factors of the following expression x2+5x-6
andre [41]
(x-1) (x+6) is the answer

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Please help me ASAP 50 points
Arte-miy333 [17]

Answer:

x=2

Vertex (2,-8)

Intercepts: 2 ±2/3 sqrt(6)

Because the parabola opens upwards, it has a minimum at the vertex

Domain:  all real numbers

Range: y>= -8

Step-by-step explanation:

y= 3x^2 -12x+4

To find the axis of symmetry, we use the formula

h= -b/2a  where ax^2 +bx+c

h = -(-12)/2*3 = 12/6=2

The axis of symmetry is x=2

The x coordinate of the vertex is at the axis of symmetry. To find the y coordinate, substitute x into the equation

y= 3(2)^2 -12(2) +4

y = 3*4-24+4

  = 12-24+4

  = -8

The vertex is at (2,-8)

We can use the quadratic formula to find the x intercepts

x = -b ±sqrt(b^2-4ac)

    -----------------------

           2a

  =  12 ± sqrt(12^2 - 4*3*4)

  ---------------------------------

    2*3

=   12± sqrt(144-48)

 ----------------------

  6

= 12±sqrt(96)

---------------

6

=2 ±1/6 * 4sqrt(6)

= 2 ±2/3 sqrt(6)


Because the parabola opens upwards, it has a minimum at the vertex.

The domain is the values that x can take.

X can be all real numbers

The range is the values that y can take.  Since there is a minimum, y must be greater than that minimum

Range: y>= -8

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Answer: 7.9

Step-by-step explanation:

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1 year ago
What sentence uses symbols to show a relationship when two numbers are not equal?
mel-nik [20]

Answer:

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b≠a

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