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Gelneren [198K]
3 years ago
9

N is a positive integer.Explain why n(n-1) must be an even number.

Mathematics
1 answer:
V125BC [204]3 years ago
4 0

Answer:

n and (n - 1) are consecutive integers.

Step-by-step explanation:

We are given 'n', a positive integer.

This 'n' can either be odd or even.

Case I:

When 'n' is odd

The n - 1 is even.

Note that the product of odd and even is always even. That is the product of n and (n - 1) is even.

Case II:

when 'n' is even

Then n - 1 is odd.

Again, using the similar logic we can say that the product of n and n - 1 should be even because here, 'n - 1' is even and 'n' is odd.

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SOLUTION

From the question, we are told that y varies inversely as x

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\begin{gathered} y=\frac{k}{x} \\ 8=\frac{k}{10} \\ k=8\times10 \\ k=80 \end{gathered}

Now, we will substitute k for 80 back into the formula to get the inverse function, we have

\begin{gathered} y=\frac{k}{x} \\ y=\frac{80}{x} \end{gathered}

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