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pshichka [43]
2 years ago
6

Into how many equal parts can the same cake be cut if the cuts can only be made along the gridlines? cake can be cut into equal

parts.

Mathematics
1 answer:
avanturin [10]2 years ago
3 0

Into how many equal parts can the same cake be cut if the cuts can only be made along the gridlines, cake can be cut into 20 equal parts.

This is further explained below.

<h3>What are gridlines?</h3>

Generally, In spreadsheet software, gridlines are the light gray lines that divide the cells, rows, and columns. Gridlines are often used to maintain track of data. Gridlines are widely used in popular spreadsheet programs like Spreadsheet.

In conclusion, If the cuts can only be done along the gridlines, the cake may be divided into 20 equal pieces when cutting along the lines.

Read more about gridlines

brainly.com/question/2773987

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Sam is using the expression 8mn in class. What is the value of the expression when m = 4 a n d n = 12 ?
goldfiish [28.3K]

Answer:

8 x 4 x 12 = 384

Step-by-step explanation:

8 x 4 x 12 = 384

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Nhich equation results from taking the square root of both sides of (x+9)2=25
ale4655 [162]

Answer:

square root of 25=5 and square root of (x+9)=(x+9) so the answer is.... x+9=+-5

Step-by-step explanation:

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3 years ago
1 m = 3.28 ft<br><br> About how many meters are in 41 feet?
saveliy_v [14]

Answer:

12.4968

Step-by-step explanation:

plz mark me brainlest and hope this helps

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3 years ago
There are 3.9 milligrams of calcium in a ½ ounce of cooked chicken. How many milligrams are in 6 ounces?
snow_tiger [21]

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there are 46.80 milligrams in 6 ounces.

Step-by-step explanation:

3 0
3 years ago
The average score of all golfers for a particular course has a mean of 75 and a standard deviation of 4. Suppose 64 golfers play
Vilka [71]

Answer:

0.0228 = 2.28% probability that the average score of the 64 golfers exceeded 76.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 75, \sigma = 4, n = 64, s = \frac{4}{\sqrt{64}} = 0.5

Find the probability that the average score of the 64 golfers exceeded 76.

This is 1 subtracted by the pvalue of Z when X = 64.

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{76 - 75}{0.5}

Z = 2

Z = 2 has a pvalue of 0.9772

1 - 0.9772 = 0.0228

0.0228 = 2.28% probability that the average score of the 64 golfers exceeded 76.

6 0
3 years ago
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