A parallel line has the same slope as the original line. So in this case the slope of the line is also 3/4. Now how do we know if it intersects the point? We need to adjust the y intercept.
Currently, we know the equation of the line is y= 3/4 x + b, where b is the thing we are looking for. We also have a point, which supplies the x and y. Plug that in and solve for b
-2 = (3/4)*(12) + b
You'll get b= -11
So the equation of the parallel line intersecting the point given is y= 3/4x -11.
I am assuming that the slope is 3/4 based on the way you formatted the original equation, but it's the same steps if the slope is different.
Answer:
the right answer is d
I hope it is helpful for you
Without calculating, you can immediately see the absolute value sign, which implies that the final result (x) should be positive, not negative.
Answer:
No
Step-by-step explanation:
plug (6,3) into the given equation to find out
3 = 4(6-5)
3 = 4(1)
3 = 4
since 3 does not equal 4, the point (6,3) does not satisfy the equation y=4(x-5)
<span><span>x-4x+12=6
-3x+12=6
-3x+12-12=6-12
-3x=-6
-3x/-3=-6/-3
x=2
Plug (2) in for x in L2 and solve for y:
y=2(2)-6
y=4-6
y=-2
The solution (x,y)=(2,-2)
Check in both equations by substituting (x,y)=(2,-2) and see if it equals out:
L1) (2)-2(-2)=6
2+4=6
6=6 L1 checks out.
L2) (-2)=2(2)-6
-2=4-6
-2=-2 L2 checks out also, so we can say with confidence that the solution is right.
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