Answer:
35) x = 3 1/3
Step-by-step explanation:
for each of these parallelograms, the diagonals are congruent
in #35, DT = RT so you can set their expressions equal to each other
22 = 6x + 2
20 = 6x
20/6 = x
10/3 = x (simplified)
Answer:
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I believe you multiply all sides to get the area and you add all sides to get the perimeter.
Answer:
-1
Step-by-step explanation:
Formula to the determinant is:
![\left[\begin{array}{ccc}a&b\\c&d\end{array}\right] = ad-bc](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Da%26b%5C%5Cc%26d%5Cend%7Barray%7D%5Cright%5D%20%3D%20ad-bc)
0(0)–1(1)
0-1
-1
Answer = d
using the 30 - 60 - 90 triangle theorem
side across from the angle
across from angle 30 is x
across from angle 60 is x rad. 3
across from 90 is 2x
BC is across from angle 60
so BC is the x rad 3
set the given measurement equal to it
x sqrt 3 = 5
÷ sqrt 3 ÷ sqrt 3
x = (5/ sqrt 3)
multiply top and bottom by the radical to get rid of the radical in the bottom
x = (5/ sqrt 3) × (sqrt 3/sqrt 3)
x = 5 sqrt 3/ 3
since side BC is x
BC = 5 sqrt 3/ 3
* Drawing the triangle diagram would help*
