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mihalych1998 [28]
3 years ago
8

edwardo wants to find the height of a building using the sun, his height, and similar triangles. He goes out during his noon lun

ch break and comes in with a number he claims is the height of the building. What should you say to him?

Mathematics
1 answer:
FrozenT [24]3 years ago
8 0
You can indeed use similar triangles to get a side of another similar triangle.

let's say Edwardo stood next to the building and his shadow was 20ft, he's 4ft tall, and the building cast a shadow of 125ft, then, check the picture below.

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Can i please get some help
LekaFEV [45]

Answer:

3, 1, -1, -2, -3, -3, -1

Step-by-step explanation:

I used the rule they gave up top. Hope this helps :)

4 0
3 years ago
Read 2 more answers
Among persons donating blood to a clinic, 85% have Rh+ blood (that is, the Rhesus factor is present in their blood.) Six people
Leona [35]

Answer:

a) There is a 62.29% probability that at least one of the five does not have the Rh factor.

b) There is a 22.36% probability that at most four of the six have Rh+ blood.

c) There need to be at least 8 people to have the probability of obtaining blood from at least six Rh+ donors over 0.95.

Step-by-step explanation:

For each person donating blood, there are only two possible outcomes. Either they have Rh+ blood, or they do not. This means that we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem we have that:

p = 0.85, n = 6.

a) fine the probability that at least one of the five does not have the Rh factor.

Either all six have the factor, or at least one of them do not. The sum of the probabilities of these events is decimal 1. So:

P(X < 6) + P(X = 6) = 1

P(X < 6) = 1 - P(X = 6)

In which:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 6) = C_{6,6}.(0.85)^{6}.(0.15)^{0} = 0.3771

So

P(X < 6) = 1 - P(X = 6) = 1 - 0.3771 = 0.6229

There is a 62.29% probability that at least one of the five does not have the Rh factor.

b) find the probability that at most four of the six have Rh+ blood.

Either more than four have Rh+ blood, or at most four have. So

P(X \leq 4) + P(X > 4) = 1

P(X \leq 4) = 1 - P(X > 4)

In which

P(X > 4) = P(X = 5) + P(X = 6)

P(X = 5) = C_{6,5}.(0.85)^{5}.(0.15)^{1} = 0.3993

P(X = 6) = C_{6,6}.(0.85)^{6}.(0.15)^{0} = 0.3771

P(X > 4) = P(X = 5) + P(X = 6) = 0.3993 + 0.3771 = 0.7764

P(X \leq 4) = 1 - P(X > 4) = 1 - 0.7764 = 0.2236

There is a 22.36% probability that at most four of the six have Rh+ blood.

c) The clinic needs six Rh+ donors on a certain day. How many people must donate blood to have the probability of obtaining blood from at least six Rh+ donors over 0.95?

With 6 donors:

P(X = 6) = C_{6,6}.(0.85)^{6}.(0.15)^{0} = 0.3771

37.71% probability of obtaining blood from at least six Rh+ donors over 0.95.

With 7 donors:

P(X = 6) = C_{7,6}.(0.85)^{6}.(0.15)^{1} = 0.3960

0.3771 + 0.3960 = 0.7764 = 77.64% probability of obtaining blood from at least six Rh+ donors over 0.95.

With 8 donors

P(X = 6) = C_{8,6}.(0.85)^{6}.(0.15)^{2} = 0.2376

0.3771 + 0.3960 + 0.2376 = 1.01 = 101% probability of obtaining blood from at least six Rh+ donors over 0.95.

There need to be at least 8 people to have the probability of obtaining blood from at least six Rh+ donors over 0.95.

5 0
3 years ago
Given a cube with a volume of 18cm^3, what is the volume of a square pyramid that can fit perfectly inside the cube?
Galina-37 [17]
Volume of  pyramid  = 1/3 * height * area of the base

                                 = 1/3 * volume of the cube

                                 = 6 cm^3
  
6 0
3 years ago
Given: ABCD parallelogram BK ⊥ AD , AB = 6, AK = 3 Find: m∠A, m∠B, m∠C, m∠D
Troyanec [42]

Answer: Angle A = 60°, angle B = 120°, angle C = 60°, angle D = 120°

Step-by-step explanation: Please refer to the attached diagram for further details.

The question has given the parallelogram ABCD as having side AB measuring 6 units, side AK measuring 3 units and line BK has been drawn perpendicular to line AD. This means line AK forms a right angle at the point where it meets line AD. From the information provided and the figure derived from that, we have right angled triangle ABK with the right angle at point K, line AB equals 6 units and line AK equals 3 units.

Using angle A as the reference angle, line AK is the opposite (side facing the reference angle), line AB is the hypotenuse (line facing the right angle) and line AK is the adjacent (side that lies between the right angle and the reference angle).

Hence, using the trigonometric ratios,

Cos A = adjacent/hypotenuse

Cos A = 3/6

Cos A = 0.5

Checking with the calculator, (that is second function of Cos 0.5)

A = 60

The opposite sides of a parallelogram are equal (that is line AD is parallel to line BC) and therefore opposite angles are equal (that is angle A is equal to angle C).

Similarly, angle B is equal to angle D. However, angles in a quadrilateral equals 360 degrees.

Therefore, angles in parallelogram ABCD is derived as;

A + B + C + D = 360

60 + B + 60 + D = 360

120 + B + D = 360

Subtract 120 from both sides of the equation

B + D = 240

Having known that angle B equals angle D, angles B and D is derived as each half of the value 240

Angle B = 240/2

Angle B = 120

and angle D = 120

Therefore, the angles are;

A = 60, B = 120, C = 60, D = 120

3 0
3 years ago
Please answer. Will mark the brainliest and will give 20 points.
Dimas [21]

Answer: it is C

Step-by-step explanation:

5 0
3 years ago
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