Recall that a 6-bit string is a bit strings of length 6, and a bit string of weight 3, say, is one with exactly three 1's. How m
1 answer:
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Answer:
a. 54.05 Mpbs.
b. 2.745... standard deviations.
c. The z-score is 2.745....
d. The carrier's highest data speed is significantly high.
Step-by-step explanation:
a. The difference between the highest measured data speed and the mean is 72.6 - 18.55 = 54.05 Mbps.
b. The amount of standard deviations of 54.05 Mbps is equal to this value divided by the standard deviations, so we yield standard deviations.
c. The z-score is equal to the difference between the mean and a data point in standard deviations, so the z-score is 2.745....
d. 2.745... is not between -2 and 2, so the carrier's highest data speed is not insignificant - so it's significantly high.
Answer:
The solution for f(x) = g(x) are;
x = 1 and x = -1
Step-by-step explanation:
The given equations for the functions, g(x) are;
g(x) = 2 + x
The solution for f(x) = g(x), is given by equating the equations of the two functions as follows;
When f(x) = g(x), we have;
By cross multiplication, we have;
1 + 2·x = x × (2 + x) = 2·x + x²
∴ x² + 2·x - 2·x - 1 = 0
x² - 1 = 0
(x - 1)·(x + 1) = 0
x = 1, or x = -1
f(x) = g(x) = 2 + 1 = 3, or 2 - 1 = 1
Therefore, the solution for f(x) = g(x) are;
f(x) = g(x) = 3 or 1 where x = 1 and x = -1.