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jeka57 [31]
3 years ago
10

3x+4y=23 and 5x+3y=31. Solve by elimination.

Mathematics
1 answer:
mafiozo [28]3 years ago
5 0
Let 3x+4y=23 be equation 1
let 5x+3y=31  be equation 2

do (equ1)*3 and (equ2)*4

now 9x+12y=69
and <u></u>20x+12y=124
now eliminate the y by doing (equ2)-(equ1)
11x=55
x=5

now substitute x=5 back into equation 1 or 2
3*(5)+4y=23
4y=23-15
y=2
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Answer:

2\frac{1}{4}.

Step-by-step explanation:

Given:

Tina cut 3 wood boards each into 4 equal pieces.

She used 3 of the pieces for a craft.

Question asked:

What fraction of the boards does she have left ?

Write this fraction as a mixed number.

Solution:

<em><u>As she cuts 3 wood board each into 4 equal pieces :-</u></em>

Total number of equal pieces = 3\times4=12\ pieces

Pieces of wood used = 3

Remaining pieces = 12 - 3 = 9

<h3><u><em>Now, we will write these 9 pieces in terms of number of wood boards</em></u>.</h3>

<u>By unitary method:</u>

4 pieces constitute = 1 wood board

1 piece constitute = \frac{1}{4} \ wood\ board

9  pieces constitute = \frac{1}{4} \times9=\frac{9}{4} \ wood\ board

<em>Now, convert it into mixed fraction:</em>

\frac{9}{4} =2\frac{1}{4} \ wood\ board

Therefore, fraction of the boards she have left is 2\frac{1}{4}.

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Step-by-step explanation:

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