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2 years ago

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Follow this link to view Juan’s work. Critique Juan’s work by justifying correct solutions and by explaining any errors he made.

For any errors made, provide and explain a correct response. Be sure to explain each key aspect of the graph.

1 answer:

amm18122 years ago

7 0

Hey I’m sorry I don’t actually know the answer to this I’m working on it rn but if u did find out the answer to this do u mind helping me. I’m sorry and thank uu. Like if there was a sample answer to that can u reply to me with it. I’m really struggling here any help would be greatly appreciated

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The local office supply store charges $0.08 per page to make photocopies. Lionel paid $20.00 for a set of copies. How many pages

Darina [25.2K]

Answer:

250

Step-by-step explanation:

You do 20/.08 to get 250.

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3 years ago

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A company rents water tanks shaped like a cylinders. Each tank has a diameter of 12 feet and a height of 3 feet. The cost is $2

12345 [234]

Answer:

$\$678.58$

Step-by-step explanation:

step 1

<u>Find the volume of the tank</u>

we know that

The volume of a cylinder (water tank) is equal to

$V=\pi r^{2}h$

in this problem we have

$r=12/2=6\ ft$ -----> the radius is half the diameter

$h=3\ ft$

substitute

$V=\pi (6^{2})(3)=339.29\ ft^{3}$

step 2

Find the cost

$339.29\ ft^{3}*2\frac{\$}{ft^{3}}=\$678.58$

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3 years ago

Give me authentic answers please.

nataly862011 [7]

B - the value of x is positive and the value of y is negative

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3 years ago

What is 2 to the first power?

Colt1911 [192]

2 to the first is 2 because there is only one 2

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3 years ago

An open-top box with a square base is to have a volume of 4 cubic feet. Find the dimensions of the box (in ft) that can be made

Lemur [1.5K]

Answer:

The dimension of box= $2ft\times 2ft\times 1ft$

Step-by-step explanation:

We are given that

Volume of box=4 cubic feet

Let x be the side of square base and h be the height of box

Volume of box= $lbh=x^2h$

$4=x^2h$

$h=\frac{4}{x^2}$

Now, surface area of box,A= $x^2+4xh$

$A=x^2+4x(\frac{4}{x^2})=x^2+\frac{16}{x}$

$\frac{dA}{dx}=2x-\frac{16}{x^2}$

$\frac{dA}{dx}=0$

$2x-\frac{16}{x^2}=0$

$2x=\frac{16}{x^2}$

$x^3=8$

$x=2$

$\frac{d^2A}{dx^2}=2+\frac{32}{x^3}$

Substitute x=2

$\frac{d^2A}{dx^2}=2+\frac{32}{2^3}=2+4=6>0$

Hence, the area of box is minimum at x=2

Therefore, side of square base,x=2 ft

Height of box,h= $\frac{4}{2^2}=1 ft$

Hence, the dimension of box= $2ft\times 2ft\times 1ft$

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2 years ago