(7t-2) - (-3t+1) = -3*(1-3t)
First distribute:
7t-2+3t-1 = -3+9t
Now get all the terms with 't' on the same side by subtracting/adding:
7t+3t-9t = -3+2+1
Combine the terms:
1t=0
t=0
Check:
Plug in 0 for t and see if both sides of the equation come out the same:
Does (7(0)-2) - (-3(0)+1) = -3(1-3(0)) ?
(-2) - (1) = -3(1) ?
-3 = -3 ?
Yes! It works, so t=0!
Answer:
the answer would be 36.04,
Step-by-step explanation:
im gonna just leave this blank
Dy/dx = (ycos(x))/(1 + y²)
(1 + y²)/y dy = cos(x) dx
(1/y + y) dy = cos(x) dx
Integrating:
ln(y) + y²/2 = sin(x) + c
ln(1) + 1/2 = sin(0) + c
c = 1/2
Thus,
ln(y) + y²/2 = sin(x) + 1/2
