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zysi [14]
4 years ago
8

What is the probability of rolling a number less than or equal to 8 with two dice, given that at least one of the dice must show

a 6?
Mathematics
2 answers:
jeka57 [31]4 years ago
7 0
List you need to see how many of are less than of euqal to 8.
(6, 1)
(6, 2)
(6, 3)
(6, 4)
(6, 5),
6, 6)
(5, 6),
4, 6)
(3, 6)
(2, 6)
(1, 6<span>)
</span>
den301095 [7]4 years ago
5 0

Answer:

9/11

Step-by-step explanation:

I just got it right

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Evaluate 4.7j-6.8k when j=5 and k=3
creativ13 [48]

Answer:

3.1

Step-by-step explanation:

After substitution of the givens, the expression 4.7j-6.8k takes on the value

4.7(5) - 6.8(3) = 23.5 - 20.4 = 3.1

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Yuliya22 [10]

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3 years ago
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Find the value of two numbers if their sum is 16 and their difference is 2.4
Verdich [7]

Lets x and y are the value of two numbers.

x + y = 16

x - y = 2.4

If x + y = 16 then x = 16 - y

Substitute x = 16 - y into x - y = 2.4

16 - y - y = 2.4

16 - 2y = 2.4

2y = 13.6

 y = 6.8

x = 16 - y

x = 16 - 6.8

x = 9.2

Answer:

The value of two numbers are 9.2 and 6.8

7 0
3 years ago
What is meaning of <br> 34+35= ?
Elis [28]

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lol

Step-by-step explanation:

3 0
3 years ago
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What is 2 (log Subscript 3 Baseline 8 + log Subscript 3 Baseline z) minus log Subscript 3 Baseline (3 Superscript 4 Baseline min
Ilya [14]

Answer:

Value of expression in single logarithm is \log_3\left(2z^2\right).

Step-by-step explanation:

Given expression is,

2\left(\log_3\left(8\right)+\log_3\left(z\right)\right)-\log_3\left(3^4-7^2\right)

Now using logarithmic rule to solve the expression as follows,

Applying product rule of logarithmic,

\log_c\left(a\right)+\log_c\left(b\right)=\log_c\left(ab\right)

Therefore,

2\log_3\left(8z\right)-\log_3\left(3^4-7^2\right)

Applying power rule of logarithmic,

a\log_c\left(b\right)=\log_c\left(b^a\right)

Therefore,

\log_3\left(\left(8z\right)^2\right)-\log_3\left(3^4-7^2\right)

\log_3\left(\left(64z^2\right)\right)-\log_3\left(3^4-7^2\right)

Applying quotient rule of logarithmic,

\log_c\left(a\right)-\log_c\left(b\right)=\log_c\left(\frac{a}{b}\right)

Therefore,

\log_3\left(\dfrac{\left(64z^2\right)^2}{3^4-7^2}\right)

Simplifying,

\log_3\left(\dfrac{\left(64z^2\right)^2}{81-49}\right)

\log_3\left(\dfrac{\left(64z^2\right)^2}{32}\right)

\log_3\left(2z^2\right)

Therefore value of expression is \log_3\left(2z^2\right)

6 0
4 years ago
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