Answer:
- 3 and 5 if "." marks thousands
- 2, 3, 5, 6 if "." is a decimal point
Step-by-step explanation:
The number 2145 is not even, so will not be divisible by 2 or 6. It ends in 5 so is divisible by 5. Its sum of digits is 12, which is divisible by 3, so the number is divisible by 3.
2145 is divisible by 3 and 5.
2.145 is divisible by all of these numbers:
2.145/2 = 1.0725
2.145/6 = 0.3575
2.145/5 = 0.429
2.145/3 = 0.715
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Here, we take the mixed number to be divisible if the decimal representation of the quotient is a terminating decimal fraction.
Answer:
9.37 divide by two = 4.685
4.685 in 2DP = 4.68
Step-by-step explanation:
i hoped this helps.
Answer:
15.625
Step-by-step explanation:
V=wxhxl=2.5x2.5x2.5=15.625
Answer:
The goal in solving an equation is to get the variable by itself on one side of the equation and a number on the other side of the equation. To isolate the variable, we must reverse the operations acting on the variable. We do this by performing the inverse of each operation on both sides of the equation.
Reverse addition and subtraction (by subtracting and adding) outside parentheses. Reverse multiplication and division (by dividing and multiplying) outside parentheses. When multiplying or dividing by a negative number, flip the inequality sign. It does not matter if the number being divided is positive or negative
It's necessary to apply inverse operations on both sides of the equals signs so that you can solve for the variable and balance the equation.
Multi-step inequalities are solved using the same processes that work for solving equations with one exception. When you multiply or divide both sides of an inequality by a negative number, you must reverse the inequality symbol. (Much like when you divide by a negative number, the sign of the inequality must flip! Here's why: When you multiply both sides by a negative value you make the side that is greater have a "bigger" negative number, which actually means it is now less than the other side!)
You haven't provided the steps.
mathisfun.com/geometry/construct-linebisect.html
Here is a useful link to the correct steps. The instructions may not be exactly the same but I think you can do it.
