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3 years ago

Any help with this please, thank you It is not B or D

Mathematics

2 answers:

Andre45 [30]3 years ago

8 0

I think it’s c hope this helps

Andrew [12]3 years ago

3 0

Answer:

Step-by-step explanation:

its a because its positive

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The scale in the drawing is 2 inches : 3 feet. What are the length and width of the actual room? *

patriot [66]

drawing isn't shown, pls take a screenshot or photograph the exercise

5 0

3 years ago

Tan 3A in terms of tan

Zanzabum

Here's the sum rule for the tangent function:

$\tan(a+b)=\dfrac{\tan(a)+\tan(b)}{1-\tan(a)\tan(b)}$

In the special case a=b, this becomes the double angle formula:

$\tan(a+a)=\tan(2a)=\dfrac{\tan(a)+\tan(a)}{1-\tan(a)\tan(a)}=\dfrac{2\tan(a)}{1-\tan^2(a)}$

In your case, you case use the sum rule once:

$\tan(3a)=\tan(2a+a)=\dfrac{\tan(2a)+\tan(a)}{1-\tan(2a)\tan(a)}$

And use it again, in the special case of the double angle:

$\dfrac{\dfrac{2\tan(a)}{1-\tan^2(a)}+\tan(a)}{1-\dfrac{2\tan(a)}{1-\tan^2(a)}\tan(a)}$

We can obvisouly simplify this expression a lot: let's deal with the numerator and denominator separately: the numerator is

$\dfrac{2\tan(a)}{1-\tan^2(a)}+\tan(a) = \dfrac{2\tan(a)+\tan(a)-\tan^3(a)}{1-\tan^2(a)}$

and the denominator is

$1-\dfrac{2\tan(a)}{1-\tan^2(a)}\tan(a) = \dfrac{1-\tan^2(a)-2\tan^2(a)}{1-\tan^2(a)} = \dfrac{1-3\tan^2(a)}{1-\tan^2(a)}$

So, the fraction is

$\dfrac{2\tan(a)+\tan(a)-\tan^3(a)}{1-\tan^2(a)}\cdot \dfrac{1-\tan^2(a)}{1-3\tan^2(a)} = \dfrac{2\tan(a)+\tan(a)-\tan^3(a)}{1-3\tan^2(a)}$

8 0

4 years ago

What is the opposite reciprocal of 1/-3

Nataly [62]

Answer:

-3

Step-by-step explanation:

hope this helps

5 0

3 years ago

Read 2 more answers

Part A: The sun produces 3.9 ⋅ 1033 ergs of radiant energy per second. How many ergs of radiant energy does the sun produce in 3

jolli1 [7]

Answer:

Step-by-step explanation:

Given that :

Radiant energy produced per second = 3.9 * 10^33 ergs

Amount of radiant energy produced in (t) = 3.25 * 10^3 s

Radiant energy per second * time

(3.9 * 10^33) * (3.25 * 10^3)

12.675 * 10^(33 + 3)

12.675 * 10^36 ergs

= 1.2675 * 10^37 ergs

Reasonable distance for measuring tracks on a railroad:

1.435 ⋅ 10−3 mm or 1.435 ⋅ 103 mm?

1.435 × 10^-3 mm = 0.001435 mm

1.435 × 10^3 mm = 1435mm

1.435 × 10^3 mm seems more reasonable

6 0

3 years ago

For the coordinate (0,-3) the translation would be down 3.<br><br> A: True<br> B: False

Likurg_2 [28]

A True
Shifting the origin to (0,-3) would be a translation of down 3

7 0

3 years ago