Okay so for number 3, you have to do the top work first.
3: POSITIVE 2!! first, you do the stuff inside the parentheses first because of P(parentheses)EMDAS. so, 14-2-10! -2-10 is -12 and then plus positive 14 is +2. but, the negative sign outside of the parentheses makes that +2 a -2.
but, you cant forget the -12 outside. you have to do -12-2 which gets you -14. then, this is easy! -14 divided by -7 is a positive 2!
5: POSITIVE 3!! again, do the stuff in the parentheses first!! -2-4 is -6. then, -6 x 2 is -12! so, divide -12 by -4 and you get a positive 3!
Assume a is not divisible by 10. (otherwise the problem is trivial).
<span>Define R(m) to be the remainder of a^m when divided by 10. </span>
<span>R can take on one of 9 possible values, namely, 1,2,...,9. </span>
<span>Now, consider R(1),R(2),......R(10). At least 2 of them must have the sames value (by the Pigeonhole Principle), say R(i) = R(j) ( j>i ) </span>
<span>Then, a^j - a^i is divisible by 10.</span>
Answer:
−a^2 b^2 + 2a + 2b
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a^2
Step-by-step explanation:
<u><em>Please mark as brainliest if answer is right</em></u>
Have a great day, be safe and healthy
Thank u
XD
I think its D. $1,800 because 10.4 multiplied by twelve is 124.8 and if you multiply that by 15 you get $1.872.
Yes u can. It is very easy
