The sum of two consecutive odd integers is 236. What is smaller integers

1 answer:

6 0

I'll say the first integer is x. The next consecutive odd number would be x+2. If the sum of the odd integers is 236, the equation would be
x + (x + 2) = 236
solve for x
2x + 2 = 236
subtract 2 from each side of the equation
2x = 234
divide both sides by 2
x = 117
117 is the first odd integer. to find the other integer (x + 2), substitute 117 for x, and you have 117 + 2, which equals 119
The two consecutive odd integers that add up to 236 are 117 and 119.

You might be interested in

last week shiras fruit stand sold 1 3/4 boxes of peaches down the road tommys fruit stand sold 2 1/2 times as many boxes of peac

Sedaia [141]

The answer is 4 3/8 boxes because 1 3/4 x 2 1/2 ＝ 4 3/8.

6 0

3 years ago

MathematicalUse Number Sense Duane and Mick are savingtheir money to build a tree house. Duane adds $5 to their piggybank every

Elina [12.6K]

Assuming they start saving at 0 dollars

45=total=duanesavings+micksavings
duanesavings=confusing, I will explain
mick savings =amount saves per week times number of weeks

duane saves 5 dollars every other week, aka 2.5 dollars per 1 week
DS=2.5w
MS=2w

since they save at same time and at that week, when the weeks are equal (w=w), 45 it total

DS+MS=45
2.5w+2w=45
4.5w=45
divide by 4.5 both sides
w=10

10 weeks

8 0

3 years ago

Subtract the following equation

Ksenya-84 [330]

Answer:

its just a black screeeeen

Step-by-step explanation:

8 0

3 years ago

Enter the values of h and I so that y=x2+6x+10 is in vertex form<br> Y=(x+__)^2+___

DiKsa [7]

$Use\ (a+b)^2=a^2+2ab+b^2\qquad(*)\\\\y=x^2+6x+10=x^2+2(x)(3)+10=\underbrace{x^2+2(x)(3)+3^2}_{(*)}-3^2+10\\\\=(x+3)^2-9+10=(x+3)^2+1\\\\Answer:\ \boxed{y=(x+3)^2+1}$

3 0

3 years ago

A small box of cereal weighs k grams. A jumbo box of cereal weighs 5 times as much.

mariarad [96]

Answer:

k=m/5

Step-by-step explanation:

explained in the attached pi

3 0

2 years ago