A computer can do 1000 operations in 4.5×10 to the -6 power seconds how many operations can be done by this computer in one hour
1 answer:
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Answer:
P(6,-π/6) = (6, -π/6 + 2nπ) and P(-6,-π/6) = (-6, -π/6 + (2n+1)π)
Step-by-step explanation:
We need to find all polar coordinates of
The polar coordinates of any point can be reresented by (r,Ф)
where
(r,Ф) = (r, Ф+2nπ) where n is any integer and r is positive
and
(r,Ф) = (-r, Ф+(2n+1)π) where n is any integer and r is negative.
So, in the question given, r = 6 and Ф = -π/6
So, Polar coordinates will be:
P(6,-π/6) = (6, -π/6 + 2nπ) where where n is any integer and r is positive
and
P(-6,-π/6) = (-6, -π/6 + (2n+1)π) where n is any integer and r is negative.