X+9=27, so to move the nine over to the other side of the equal sign, x=27-9, x=18
Answer:
841
Step-by-step explanation:
If the number is divided by 4 and the remainder is 1, the last digit must be 1, 3, 5, 7 or 9.
If the number is divided by 5 and the remainder is 1, the last digit must be 6 or 1.
So we already know the last digit must be 1.
The numbers between 800 and 900, with last digit 1, that divided by 6 have a remainder of 1 are:
811, 841, 871
The numbers between 800 and 900, with last digit 1, that divided by 7 have a remainder of 1 is just 841
So Tommy's number is 841.
Answer:
c. no real solutions
Step-by-step explanation:
because:
1. 10+6x=15+9x-3x
6x+10=15+9x-3x
2. 6x+10=15+9x-3x
6x+10=15+6x
3. 6x+10=15+6x
6x+10=6x+15
4. 6x+10=6x+15
6x+10-10=6x+15-10
5. 6x=6x+5
6. 6x=6x+5
6x-6x=6x+5-6x
Then you get:
0=5
remember, If you want to know if an equation has no equation:
the constants are the numbers alone with no variables. If the coefficients are the same on both sides then the sides will not equal, therefore no solutions will occur. Use distributive property on the right side first.
I hope this helps :)
Check the picture below.
so if x = 4, then 2x? surely you know that.
