Answer:
y = (1/2)x + 5/2
Step-by-step explanation:
y - 3 = (1/2)(x - 1) is in point-slope form. To obtain the slope-intercept equivalent, solve this equation for y:
y = 3 + (1/2)x - 1/2, or
y = (1/2)x + 3 - 1/2, or
y = (1/2)x + 5/2
The answer is: -4/a^2 b^2
The answer would be, y=-x+2
The cross product of the normal vectors of two planes result in a vector parallel to the line of intersection of the two planes.
Corresponding normal vectors of the planes are
<5,-1,-6> and <1,1,1>
We calculate the cross product as a determinant of (i,j,k) and the normal products
i j k
5 -1 -6
1 1 1
=(-1*1-(-6)*1)i -(5*1-(-6)1)j+(5*1-(-1*1))k
=5i-11j+6k
=<5,-11,6>
Check orthogonality with normal vectors using scalar products
(should equal zero if orthogonal)
<5,-11,6>.<5,-1,-6>=25+11-36=0
<5,-11,6>.<1,1,1>=5-11+6=0
Therefore <5,-11,6> is a vector parallel to the line of intersection of the two given planes.
Answer:
You would want to do the square root of 361 which is 19
Hope This Helps!
ps. no, I'm not stalking u I just clicked on the next question from your last one.