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3 years ago

How do solve this problem?

Mathematics

2 answers:

Ira Lisetskai [31]3 years ago

6 0

The perimeter in the out side rim of somthing.
This is the formula
Perimeter =2(l+w)

Sloan [31]3 years ago

4 0

Perimeter of the whole shabang should be (7*2)+(5*2)

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Suppose that Clayton Kershaw of the Los Angeles Dodgers throws his fastball with a mean velocity of 94 miles per hour (mph) and

vekshin1

Answer:

Step-by-step explanation:

ah, probability, so the std. deviation is 2 MPH, so that means to get from the mean.. or average speed of 94, he'll have to vary by 3 std. deviations or 6 MPH to hit 100

99.7% of throws fall into that area of with in 3 std. deviations so that means

0.3% fall outside also , 1/2 of those will 3 std. deviations slow while the other half is fast

0.15% will be 100 or faster.... not many

8 0

2 years ago

Please help and thank you

Rainbow [258]

Answer:

odp c

Step-by-step explanation:

17*8=136

6 0

2 years ago

If A has the coordinate -10 and C has the coordinate 14 and B is the midpoint of a AC, then what is the coordinates of D which i

salantis [7]

Answer:

Step-by-step explanation:

The midpoint of AC is ...

B = (A +C)/2 = (-10 +14)/2 = 2

The midpoint of BC is ...

D = (B +C)/2 = (2 +14)/2 = 8

The midpoint of BC is 8.

5 0

2 years ago

Question Help

Sergeeva-Olga [200]

Answer:

if u divide it then slop it u will get your answer

3 0

2 years ago

A woman bought some large frames for $10 each and some small frames for $5 each add a closeout sale if she bought 20 frames for

vampirchik [111]

Answer:

The quantity of large frames is 7

The quantity of small frames is 13

Step-by-step explanation:

Given as :

The price of each large frames = $ 10

The price of each small frames = $ 5

The total number of both frames bought = 20

The price for both the frames = $ 135

Now,

Let the quantity of large frames = L

And The quantity of small frames = S

So , According to question

The total number of both frames bought = 20

Or, The quantity of large frames + the quantity of small frame = 135

Or, L + S = 20 ......A

And $ 10 L + $ 5 S = $ 135 ................B

Or, $ 10× ( L + S ) = $ 10× 20

Or, $ 10 L + $ 10 S = $ 200

( $ 10 L + $ 10 S ) - ( $ 10 L + $ 5 S ) = $ 200 - $ 135

Or , ( $ 10 L - $ 10 L ) + ( $ 10 S - $ 5 S ) = $ 65

Or, 0 + 5 S = 65

∴ S = $\frac{65}{5}$

I.e S = 13

So, The quantity of small frames = S = 13

Put the Value of S in eq A

So , L + S = 20

Or, L = 20 - S

Or, L = 20 - 13

∴ L = 7

So, The quantity of large frames = L = 7

Hence The quantity of large frames is 7

And The quantity of small frames is 13 Answer

7 0

3 years ago