1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
madreJ [45]
3 years ago
14

How do solve this problem?

Mathematics
2 answers:
Ira Lisetskai [31]3 years ago
6 0
The perimeter in the out side rim of somthing.
This is the formula
Perimeter =2(l+w)

Sloan [31]3 years ago
4 0
Perimeter of the whole shabang should be (7*2)+(5*2)

You might be interested in
Can someone plz help me
Sati [7]

Answer:

One point greater than the last grade

Step-by-step explanation:

1. First off, N is the variable, so that means it can be any number, and when it uses the word <em>greater</em>, it means to ADD another number, which means one point greater.

6 0
3 years ago
Read 2 more answers
An educational psychologist wishes to know the mean number of words a third grader can read per minute. She wants to make an est
nirvana33 [79]

Answer:

The 80% confidence interval for the mean number of words a third grader can read per minute is between 40.4 wpm and 40.8 wpm.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.8}{2} = 0.1

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.1 = 0.99, so z = 1.28

Now, find M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

M = 1.28*\frac{4.1}{\sqrt{840}} = 0.2

The lower end of the interval is the sample mean subtracted by M. So it is 40.6 - 0.2 = 40.4 words per minute.

The upper end of the interval is the sample mean added to M. So it is 40.6 + 0.2 = 40.8 words per minute.

The 80% confidence interval for the mean number of words a third grader can read per minute is between 40.4 wpm and 40.8 wpm.

3 0
4 years ago
5. Shelly spent $15.73 at the mall. Her sister Kelly spent $7.92. How much more did Shelly spend than Kelly? Answer using number
Allushta [10]

Answer:

$7.81

Step-by-step explanation:

$15.73-$7.92

7 0
3 years ago
The officers of a high school senior class are planning to rent buses and vans for a class trip. Each bus can transport 6363 ​st
attashe74 [19]

Answer:

  • 1 bus, 72 vans
  • $6960 is the minimum cost

Step-by-step explanation:

A bus costs over $19 per student; a van costs less than $12 per student. The required number of students could be transported by 81 vans, but that requires 81 chaperones.

Since there are only 80, and a bus requires fewer chaperones per student, we can reduce the number of required chaperones to an acceptable level by employing one bus. 1 bus replaces 9 vans, and requires 1 less chaperone than 9 vans.

The minimum cost is 1 bus and 72 vans. That cost is $1200 +72×$80 = $6960.

3 0
3 years ago
3 10/15-1 12/15 hurry i need to pass this please
navik [9.2K]

Answer:

1 13/15

Step-by-step explanation:

3−1=2

10/15−12/15=−2/15

2−2/15=1 13/15

4 0
3 years ago
Read 2 more answers
Other questions:
  • Which statement is true about regular exercise? 1.It decreases your resting heart rate.
    8·2 answers
  • Which expression is equivalent to
    7·2 answers
  • (-4n2 - 24 +n- 9n) divided by (2+5)
    9·1 answer
  • In a one-way ANOVA, what is the difference between the among-groups variance MSA and the within-groups variance MSW?
    6·1 answer
  • What is 2 2 3 ÷ 2 3 ?
    13·2 answers
  • URGENT PLEASE HELP! What is the slope of the line <br> y = -2x - 4?
    7·1 answer
  • Man help plzzz ive been struggling
    10·1 answer
  • Counting numbers greater than 110
    7·1 answer
  • (a) Reflect the point (7, -9) across the y-axis:
    9·2 answers
  • What is the absolute value of <img src="https://tex.z-dn.net/?f=-%5Cfrac%7B10%7D%7B3%7D" id="TexFormula1" title="-\frac{10}{3}"
    8·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!