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Morgarella [4.7K]
4 years ago
7

A Gallup Poll found that 51% of the people in its sample said "yes" when asked, "Would you like to lose weight?" Gallup announce

d: "With 95% confidence for results based on the total sample of national adults, one can say that the margin of sampling error is ± 3%."
Mathematics
1 answer:
Nata [24]4 years ago
4 0

Answer:

(a) 95% confidence interval for the percent of all adults who want to lose weight is (48%, 54%) that is between 48% and 54%

(b) to say that we have 95% confidence in this interval means that there is 95% chance that the true percentage of all adults who wants to lose weight falls in this interval.

Step-by-step explanation:

The question is missing, complete question is below:

A Gallup Poll found that 51% of the people in its sample said "yes" when asked, "Would you like to lose weight?" Gallup announced: "With 95% confidence for results based on the total sample of national adults, one can say that the margin of sampling error is ± 3%."

(a) What is the 95% confidence interval for the percent of all adults who want to lose weight?

(b) What does it mean to say that we have 95% confidence in this interval?

Confidence Interval can be calculated using p±ME where

  • p is the sample proportion of national adults who want to lose weight (51%)
  • ME is the margin of sampling error (± 3%)
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z + z + 6


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2z + 6 is an expresssion equivalent to z + (z+6)


Hope this helps!



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Whats 603X4 estimate go math
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Ivanshal [37]

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Usha thinks that the area of the development will be greater than the total area of 50 football pitches.
tangare [24]

Answer:

Usha is correct

Step-by-step explanation:

See attachment

Given

Dimension of the development

Height = \frac{1}{2}\ mile

Base = \frac{1}{2}\ mile

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First, we calculate the area of the development.

Because it is triangular in shape, the area is:

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Convert mile to meter

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<em>Hence, Usha's thought is correct</em>

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