How to solve radical 28 plus radical 64

1 answer:

8 0

The solution to the problem is as follows:

√28 = √(4 * 7) = √4 * √7 = 2√7.

√64 = 8

Therefore, √28 + √64 = 2√7. + 8

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!

You might be interested in

Find 2 + 3(7 - 2) this

Ivahew [28]

Answer:

2+3=5(7-2)

5(7-2)

5(5)

Step-by-step explanation:

3 0

4 years ago

A national publication showed the following distribution of favorite class subjects for high school students.

matrenka [14]

Answer:

1 and 111 only

Step-by-step explanation:

The goodness of fit test is used to examine if there is significant evidence to say thatvthe observed and expected freqencies are from the desired distribution.

Condituis required for performing a goodness of fit test on a data include :

Randomness, sampled Data must have been chosen at random in other to be representative, here, randomness isn't exhibited as Pasquale used more of convenient sampling questioning the first 40 students.

Also, the expected value of the number of sample observation in each level of the variable should be atleast 5.

This is also violated, as the expected values for some of the levels are less than 5

Hence, conditions 1 and 111 are not met

7 0

3 years ago

Find the coordinates of the intersection of the diagonals of parallelogram HJKL with the given vertices: H(-1, 4), J(3, 3), K(3,

lakkis [162]

Answer:

(1, 1)

Step-by-step explanation:

Given vertices of the parallelogram:

H = (-1, 4)
J = (3, 3)
K = (3, -2)
L = (-1, -1)

Therefore the parallel sides are:

$\sf \overline{HJ} \parallel \overline{LK}\:\: \textsf{ and }\:\: \overline{LK} \parallel \overline{HL}$

Therefore, the diagonals of the parallelogram are:

$\sf \overline{LJ} \:\: \textsf{ and }\:\:\overline{HK}$

To find the coordinates of the intersection of the diagonals, either:

draw a diagram (see attached) and determine the point of intersection of the diagonals from the diagram, or
determine the midpoint of either diagonal (as the diagonals of a parallelogram bisect each other, i.e. divide into 2 equal parts).

Midpoint between two points

$\textsf{Midpoint}=\left(\dfrac{x_2+x_1}{2},\dfrac{y_2+y_1}{2}\right)\quad \textsf{where}\:(x_1,y_1)\:\textsf{and}\:(x_2,y_2)\:\textsf{are the endpoints}}\right)$

To find the midpoint of diagonal LJ, define the endpoints:

$(x_1,y_1)=L=(-1, -1)$
$(x_2,y_2)=J=(3,3)$

Substitute the defined endpoints into the formula and solve:

$\begin{aligned} \implies \textsf{Midpoint of LJ} & =\left(\dfrac{3-1}{2},\dfrac{3-1}{2}\right)\\ & =\left(\dfrac{2}{2},\dfrac{2}{2}\right)\\ & =\left(1,1\right) \end{aligned}$