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Alekssandra [29.7K]
3 years ago
6

Ron Finley is a gardener who decided a few years ago to plant several gardens in South Central Los Angeles. He wants his next ga

rden to be a rectangle where the length is three times the width. Additionally, it must have a perimeter of 24 yards because of space constraints. What are the length and the width of the garden?
Mathematics
1 answer:
yaroslaw [1]3 years ago
3 0

Well, we can be sure that whatever the width is, we can call it ' W '. Then, from information in the question, the length of the garden is ' 3W '.

Now, the perimeter of a rectangle is (length + width + length + width). Using the fancy algebra labels I just gave them, that's (3W + W + 3W + W). And now I can go through that, add up all the Ws, and get a total of 8W for the perimeter.

But he question tells us that the perimeter is 24 yards, so 8W = 24 yds.

Divide each side of that equation by 8, and we discover that W = 3 yds. And if THAT's true, then 3W = 9 yds. Bada bing ! We have the dimensions of the garden.

It's 3 yards wide and 9 yards long.

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120 is the same as 394 fewer than Z
SpyIntel [72]

Answer:

z=514

Step-by-step explanation:

120=z-394

+394. +394

514=z

Hope this helps

8 0
3 years ago
If l=x-4 feet, w=x-5 feet, what is the area of the patio?
solmaris [256]

Answer:

20 ft.²

Step-by-step explanation:

You can find the area (A) by multiplying the length (l) and width (w) of a shape together: l×w=A

Plug in the measurements for length and width and solve

      4×5=A

      20=A

7 0
3 years ago
The simple interest on a certain sum of money for 2 years at 5% per annum is Rs 320. What will be the compound interest on the s
Brilliant_brown [7]

Answer:

Rs 328

Step-by-step explanation:

Find the <u>principal</u> amount invested.

<u>Simple Interest Formula</u>

I = Prt

where:

  • I = interest earned
  • P = principal
  • r = interest rate (in decimal form)
  • t = time (in years)

Given:

  • I = Rs 320
  • r = 5% = 0.05
  • t = 2 years

Substitute the given values into the formula and solve for P:

⇒ 320 = P(0.05)(2)

⇒ 320 = P(0.1)

⇒ P = 3200

<u>Compound Interest Formula</u>

\large \text{$ \sf I=P\left(1+\frac{r}{n}\right)^{nt} -P$}

where:

  • I = interest earned
  • P = principal amount
  • r = interest rate (in decimal form)
  • n = number of times interest applied per time period
  • t = number of time periods elapsed

Given:

  • P = 3200
  • r = 5% = 0.05
  • n = 1 (annually)
  • t = 2 years

Substitute the given values into the formula and solve for I:

\implies \sf I=3200\left(1+\frac{0.05}{1}\right)^{2} -3200

\implies \sf I=3200\left(1.05\right)^{2} -3200

\implies \sf I=3200\left(1.1025\right) -3200

\implies \sf I=3528-3200

\implies \sf I=328

Therefore, the compound interest on the same sum for the same time at the same rate is Rs 328.

7 0
2 years ago
Smplify the expression:<br> 5+6i/4+6i
skelet666 [1.2K]
The answer would be 5 + 15i/2.

1. 5 + 3i/2 + 6i

2. 5 + (3/2i + 6i)

3. 5 + 15i/2.
5 0
3 years ago
e) Isabel’s competition,who sells books and no other products, charges a shipping fee of $1.99 per book plus a fixed fee of $3 f
inessss [21]

Answer:

It will equal 0

7 0
3 years ago
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