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3 years ago

Determine whether the relation represents a function. If it is a function, state the domain and range.

Mathematics

1 answer:

oee [108]3 years ago

3 0

Answer: Yes it is a function

Step-by-step explanation:

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Analyze tables use the table that shows the percents of blood types of 145 donors during a recent blood drive

Alenkinab [10]

Answer:

a. 16

b. 80

c. Blood type AB

Step-by-step explanation:

Given:

O = 45%

A = 40%

B = 11%

AB = 4%

Total number of donors = 145

a. No. of donors that had type B blood = $\frac{11}{100}*145 = \frac{1,595}{100} = 15.95$

Type B blood donors ≈ 16

b. No. of blood donors without blood type O = $\frac{40 + 11 + 4}{100}*145 = \frac{55}{100}*145 = \frac{7,975}{100} = 79.75$

Those without blood type O ≈ 80

c. Find the number of people that had type AB:

Type AB = $\frac{4}{100}*145 = 5.8$ ≈ 6. This is less than 10 donors.

Therefore, blood type AB had less than 10 donors.

6 0

4 years ago

Suppose a and b are both non zero real numbers. Find real numbers c and d such that 1/a+ib= c+id

Thepotemich [5.8K]

$\begin{gathered} c=\frac{a}{a^2+b^2} \\ d=\frac{-b}{a^2+b^2} \end{gathered}$

Explanation

$\frac{1}{a+bi}=c+di$

Step 1

multiplicate by the conjugate

$\begin{gathered} \frac{1}{a+bi}\cdot\frac{a-bi}{a+bi}=\frac{a-bi}{(a+bi)(a-bi)}=\frac{a-bi}{a^2-(bi)^2} \\ \frac{1}{a+bi}\cdot\frac{a-bi}{a+bi}=\frac{a-bi}{(a+bi)(a-bi)}=\frac{a-bi}{a^2-(-b^2)}=\frac{a-bi}{a^2+b^2} \end{gathered}$

notice that

$\begin{gathered} \frac{1}{a+bi}=\frac{a-bi}{a^2+b^2}=\frac{a}{a^2+b^2}-\frac{b}{a^2+b^2}i \\ \frac{a}{a^2+b^2}-\frac{b}{a^2+b^2}i=c+di \\ so \\ \end{gathered}$ $\begin{gathered} c=\frac{a}{a^2+b^2} \\ d=\frac{-b}{a^2+b^2} \end{gathered}$

I hope this helsp you

6 0

1 year ago

5.6 x 5.6 x 6.16 x 6.16

ivann1987 [24]

Answer:

5.6 x 5.6 x 6.16 x 6.16=1190

Step-by-step explanation:

5.6 x 5.6 x 6.16 x 6.16=1189.974016

Rounded up will be 1190.

8 0

3 years ago

If 15x+17*2=227<br><br> what is x

sladkih [1.3K]

X will be 35 but idk the formula

8 0

3 years ago

Question<br> Find the sum horizontally.<br> (3x – x°- 2x?)+(-x° - 3x) =

Trava [24]

Answer:

Step-by-step explanation:

you take 3x-x you get 2x. then you take 2x_2x you get 0.then -x_3x you get 2x.you take 0+2x you get 2x that is the answer

6 0

3 years ago

Determine whether the relation represents a function￼. If it is a function, state the domain and range.

Determine whether the relation represents a function. If it is a function, state the domain and range.