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Irina18 [472]
3 years ago
6

A car is driving 45 mi/h. What is the speed of the car in feet per minute

Mathematics
1 answer:
katovenus [111]3 years ago
4 0
.75 mi/minute

45/60=.75
.75 miles every minute

there are 3960 feet per minute.

You could also times 45 by 5280, since there are 5280 feet in a mile, and you would get 237,600. You would then divide it by 60, and still end up with 3960 feet per minute.

Tell me if this helps
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Gymnast Clothing manufactures expensive soccer cleats for sale to college bookstores in runs of up to 500. Its cost (in dollars)
Natalija [7]

Revenue, R = 130x

Profit, P = Revenue – Cost

 P = R – C

P = 130x – 2950 + 6x + 0.1x^2

At P = 0

0 = -2950 + 136x +0.1x^2

X = 21.355, -1381.355

Therefore, manufacture greater than 21.355 items to make profit. 

3 0
3 years ago
Read 2 more answers
Which represents the inverse of the function f(x)=4x?
Juliette [100K]

Answer:

h(x) = \frac{1}{4}x

Step-by-step explanation:

Suppose h is the inverse of f then

f(x) = y ⇔ h(y) = x

f(x) = y ⇔ 4x = y ⇔ x = y/4

and since x = h(y) then h(y) = y/4

then we can write :

h(x) = \frac{x}{4}

______________________

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8 0
3 years ago
How many numbers lie between the square of 56 and 57
NARA [144]

Answer:

Given, two numbers 56 and 57 we need to find out the numbers lie between the squares of the given numbers.

Now, we have numbers lying between the square of n and (n + 1) is 2n

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Hence, 112 numbers lies between the square of the given numbers.

7 0
3 years ago
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Find the size of each of two samples (assume that they are of equal size) needed to estimate the difference between the proporti
hodyreva [135]

Answer:

The sample size n = 4225

Step-by-step explanation:

We will use maximum error formula = \frac{z_{a} S.D}{\sqrt{n} }

but we will find sample size "n"

\sqrt{n}  = \frac{z_{a} S.D}{maximum error}

Squaring on both sides , we get

n  = (\frac{z_{a} S.D}{maximum error})^2

Given 99% confidence interval (z value) = 2.56

given maximum error = 0.02

n  = (\frac{z_{a} p(1-p)}{maximum error})^2

n≤ (\frac{2.56X\frac{1}{2} }{0.02}) ^{2}    ( here S.D = p(1-p) ≤ 1/2

on simplification , we get n = 4225

<u>Conclusion</u>:

The sample size of two samples is  n = 4225

<u>verification</u>:-

We will use maximum error formula = \frac{z_{a} S.D}{\sqrt{n} } = \frac{2.56 1/2}{\ \sqrt{4225} }  = 0.0196

substitute all values and simplify we get maximum error is 0.02

4 0
3 years ago
(x-7) and (x+6) what are the zeros of function g?
Stells [14]
Your answer is 7 and -6
3 0
3 years ago
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