Answer: (a) 0.006
(b) 0.027
Step-by-step explanation:
Given : P(AA) = 0.3 and P(AAA) = 0.70
Let event that a bulb is defective be denoted by D and not defective be D';
Conditional probabilities given are :
P(D/AA) = 0.02 and P(D/AAA) = 0.03
Thus P(D'/AA) = 1 - 0.02 = 0.98
and P(D'/AAA) = 1 - 0.03 = 0.97
(a) P(bulb from AA and defective) = P ( AA and D)
= P(AA) x P(D/AA)
= 0.3 x 0.02 = 0.006
(b) P(Defective) = P(from AA and defective) + P( from AAA and defective)
= P(AA) x P(D/AA) + P(AAA) x P(D/AAA)
= 0.3(0.02) + 0.70(0.03)
= 0.027
This is true. You can remember by it saying mid, as in middle.
Answer:
26.67X10^-2 would be incorrect since the decimal is in the wrong place.
Step-by-step explanation:
Answer:
The fraction, or the one on the right is larger by just a few decimals.
Step-by-step explanation:
Have an amazing day :D
The equation a = 100 + 75d represents Maria's account balance.
<u>Step-by-step explanation:</u>
Given that,
- Maria opened a new savings account with an initial deposit of $100.
- She deposits $75 into this savings account every two-weeks.
You need to find the equation to represent Maria's account balance, a after she has completed d deposits.
- Let 'd' be the number of deposits Maria made after the initial deposit.
- Let 'a' be the total account balance after 'd' deposits.
Therefore, the equation for the total account balance can be framed as the sum of the initial deposit and amount deposited after that.
<u>To find the amount that was deposited after the initial deposit :</u>
⇒ $75 × number of times Maria deposited.
⇒ 75 × d
The equation is written as,
⇒ a = 100 + 75d
Hence the equation a = 100 + 75d represents Maria's account balance.
