Answer:
A2 = 120
A3 = 60
A5 = 60
A6 = 120
Step-by-step explanation:
Angle 1 and 2 are supplementary, so A2 = 180 - 60, which is 120.
Angle 1 and 3 are vertical angles, which are always the same measure.
Angle 5 is alternate interior angles with 3, which means it is also 60.
Angle 6 is alternate interior angles with 4, which means it is 120.
4*4-5*3-2x+6= -x-7/2 slope = 2
3 * 3 - 4 *2 -2x +1= - x - 2/2 slope = -2
2 + -2 = 0
90 points where at least two of the circles intersect.
<h3>Define circle.</h3>
A circle is a closed, two-dimensional object where every point in the plane is equally spaced from a central point. The line of reflection symmetry is formed by all lines that traverse the circle. Additionally, every angle has rotational symmetry around the centre.
Given,
Four distinct circles are drawn in a plane.
Start with two circles; they can only come together in two places. The third circle contacts each of the previous two circles in two spots each, bringing the total number of intersections up to four with the addition of a third circle. The total number of intersections will rise by another 6 when a fourth circle intersects the first three. And the list goes on.
As a result, we get a recognizable, regular pattern: for each additional circle, there are two more intersections overall than in the circle before it.
The total number of intersections can be expressed as the sum because the maximum number of intersections of 10 circles must occur when each circle contacts every other circle in 2 places each.
2 + 4 + 6 + 8 + 10 + 12 + 14 + 16 + 18 = 90.
90 points where at least two of the circles intersect.
To learn more about circle, visit:
brainly.com/question/11213974
#SPJ4
If you want to find the diameter of a circle multiply the radius by 2
Dh-2
Answer: .625 (yes he did leave enough
Step-by-step explanation: First you need to divde the fractions( or solve them) ,so 7 divided by 8 and so on Then you take subtract the paint ivan used, if it is less than half than ivan didn't leave enough for his poor sister
but there are other ways if this one is to hard
