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dimulka [17.4K]
3 years ago
11

A number line going from negative 4 to positive 4. What is the distance between 0 and –2? Use the number line to answer the ques

tion. -2 0 1 2
Mathematics
2 answers:
vaieri [72.5K]3 years ago
5 0

Answer:

A number line going from negative 4 to positive 4.

What is the distance between 0 and –2?

Use the number line to answer the question.

-2  

0

1

2

Step-by-step explanation:

-2 is correct

batgirl1000000000000000000000
2 years ago
it is not -2 it is just 2
Nana76 [90]3 years ago
4 0

Answer:

I wish <em>i could help </em>

Step-by-step explanation:

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Same I don’t get this
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3 years ago
If x=-7 is a root of the equation x^2+kx+49=0, then k=​
aleksley [76]

Answer:

k=14

Step-by-step explanation:

Given:

x^{2}+kx+49 = 0

x = -7

Substitution can be used to find the value of k:

(-7)^{2}+(-7)k+49 = 0

49-7k+49 = 0

98 -7k = 0

k = 14

Hope this helps :)

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3 years ago
Please help FAST I need the answer along with you explaining the steps so I can get it thanks! I’ll give Brainlist also!
kupik [55]

Answer:

The equation of required line is: \mathbf{5x-8y+34=0}

Step-by-step explanation:

We need to write equation in the form Ax+By+C=0 of the line parallel to 5x-8y+12=0 and through the point (-2,3)

First we need to find slope and y-intercept of the required line.

Using equation of line  5x-8y+12=0 to find slope.

Since the given line and required lines are parallel there slope is same.

Writing equation in slope intercept form: y=mx+b where m is slope.

5x-8y+12=0 \\-8y=-5x-12\\\frac{-8y}{-8y}=\frac{-5x}{-8}-\frac{12}{-8}\\y=\frac{5}{8}x+\frac{3}{4}

So, the slope m = 5/8

The slope of required line is m=\frac{5}{8}

Now finding y-intercept using slope m=\frac{5}{8} and point(-2,3)

y=mx+b\\3=\frac{5}{8}(-2)+b\\3=\frac{-5}{4}+b\\b=3+\frac{5}{4}\\b=\frac{3*4+5}{4}\\b=\frac{12+5}{4}\\b=\frac{17}{4}

So, the equation of required line having slope m=\frac{5}{8}  and y-intercept b=\frac{17}{4}

y=mx+b\\y=\frac{5}{8}x+\frac{17}{4}\\y=\frac{5x+17*2}{8}\\y= \frac{5x+34}{8}  \\8y=5x+34\\5x-8y+34=0

So, The equation of required line is: \mathbf{5x-8y+34=0}

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Read 2 more answers
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