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dimulka [17.4K]
3 years ago
11

A number line going from negative 4 to positive 4. What is the distance between 0 and –2? Use the number line to answer the ques

tion. -2 0 1 2
Mathematics
2 answers:
vaieri [72.5K]3 years ago
5 0

Answer:

A number line going from negative 4 to positive 4.

What is the distance between 0 and –2?

Use the number line to answer the question.

-2  

0

1

2

Step-by-step explanation:

-2 is correct

batgirl1000000000000000000000
2 years ago
it is not -2 it is just 2
Nana76 [90]3 years ago
4 0

Answer:

I wish <em>i could help </em>

Step-by-step explanation:

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The function f(x) = 350 - 125x represents how
Viefleur [7K]
After one hour, the plane is 225 miles from its destination
8 0
3 years ago
Read 2 more answers
A new car depreciates as soon as you drive it out of the parking lot. A certain car depreciates to half its original value in 4
Alexandra [31]

Answer:

Original price of car = $20,000

Step-by-step explanation:

Let the original price of the car be 'x' dollars.

Given:

Here, the depreciation of the car is occuring exponentially as the value depreciates to half in every four years.

Worth of car after 8 years = $5000

Value after depreciation in 4 years = Half of original value = \frac{x}{2}

So, value of car after depreciation in another 4 years = Half of the value after 4 years = \frac{1}{2}(\frac{x}{2})=\frac{x}{4}

Therefore, final depreciated value after 8 years is \frac{x}{4}.

But, as per question, final depreciated value is $5000. Thus,

\frac{x}{4}=5000\\x=5000\times 4\\x=20000

Therefore, the original price of the car was $20,000.

3 0
3 years ago
Find the distance between (-5,6)and (3,2).
skad [1K]

Answer:

\displaystyle d = 4\sqrt{5}

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Algebra I</u>

  • Coordinates (x, y)

<u>Algebra II</u>

  • Distance Formula: \displaystyle d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Step-by-step explanation:

<u>Step 1: Define</u>

Point (-5, 6) → x₁ = -5, y₁ = 6

Point (3, 2) → x₂ = 3, y₂ = 2

<u>Step 2: Find distance </u><em><u>d</u></em>

Simply plug in the 2 coordinates into the distance formula to find distance <em>d</em>

  1. Substitute in points [Distance Formulas]:                                                     \displaystyle d = \sqrt{(3+5)^2+(2-6)^2}
  2. [Distance] [√Radical] (Parenthesis) Add/Subtract:                                       \displaystyle d = \sqrt{(8)^2+(-4)^2}
  3. [Distance] [√Radical] Evaluate exponents:                                                    \displaystyle d = \sqrt{64+16}
  4. [Distance] [√Radical] Add:                                                                             \displaystyle d = \sqrt{80}
  5. [Distance] [√Radical] Simplify:                                                                         \displaystyle d = 4\sqrt{5}
6 0
3 years ago
Watch help video
Natali5045456 [20]

Answer:

100 \div .19

4 0
3 years ago
Evaluate and simplify <br><br> F(x)=3-6x^2 for f(x+3)
Olegator [25]

Insert x + 3 instead of x into the equation of the function f(x):

f(x) = 3 - 6x²

f(x + 3) = 3 - 6(x + 3)²

use (a + b)² = a² + 2ab + b²

= 3 - 6(x² + 2(x)(3) + 3²) = 3 - 6(x² + 6x + 9)

use distributive property

= 3 + (-6)(x²) + (-6)(6x) + (-6)(9) = 3 - 6x² - 36x - 54

combine like terms

= -6x² - 36x - 51

<h3>Answer: f(x + 3) = -6x² - 36x - 51</h3>
4 0
4 years ago
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