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2 years ago

We are more aware of the _ form than the _ spaces

1 answer:

8 0

The answer is: We are more aware of the positive form than the negative spaces. In which with every movement, the connection of form and space modify. A creator should possess every angle in mind in which the form is being created and the spaces adjoining the form. Space may comprise curls, the curves, the waves, the straight hair or any arrangement. In general, it is the space which is the area surrounding the form or area that the style occupies.

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G(x)=x^3+5x h(x) =x+3 find (g+h)(x)

exis [7]

$(g+h)(x) = x^3+6x+3$

Step-by-step explanation:

The operations on functions can be performed as they are performed on polynomials

The addition of functions is used in the given question

Given

$g(x)=x^3+5x\\h(x)=x+3$

We have to find:

$(g+h)(x)=g(x)+h(x)\\=x^3+5x+x+3\\=x^3+6x+3$

So,

$(g+h)(x) = x^3+6x+3$

Keywords: Functions, operations on functions

Learn more about functions at:

#LearnwithBrainly

7 0

3 years ago

Look at the pic and answwe

DochEvi [55]

Answer:

The answer is C 40/3

Hope I Helped

7 0

3 years ago

Read 2 more answers

Which pair of numbers has an LCM of 8

maxonik [38]

Answer:

2,8

Step-by-step explanation:

3 0

2 years ago

cylinder shaped can needs to be constructed to hold 200 cubic centimeters of soup. The material for the sides of the can costs 0

Dafna11 [192]

Answer:

Radius=2.09 cm

Height,h=14.57 cm

Step-by-step explanation:

We are given that

Volume of cylinderical shaped can=200 cubic cm.

Cost of sides of can=0.02 cents per square cm

Cost of top and bottom of the can =0.07 cents per square cm

Curved surface area of cylinder= $2\pi rh$

Area of circular base=Area of circular top= $\pi r^2$

Total cost,C(r)= $0.02\times 2\pi rh+2\pi r^2\times 0.07$

Volume of cylinder, $V=\pi r^2 h$

$200=\pi r^2 h$

$h=\frac{200}{\pi r^2}$

Substitute the value of h

$C(r)=0.02\times 2\pi r\times \frac{200}{\pi r^2}+2\pi r^2\times 0.07$

$C(r)=\frac{8}{r}+0.14\pi r^2$

Differentiate w.r.t r

$C'(r)=-\frac{8}{r^2}+0.28\pi r$

$C'(r)=0$

$-\frac{8}{r^2}+0.28\pi r=0$

$0.28\pi r=\frac{8}{r^2}$

$r^3=\frac{8}{0.28\pi}=9.095$

$r=(9.095)^{\frac{1}{3}}=2.09$

Again, differentiate w.r.t r

$C''(r)=\frac{16}{r^3}+0.28\pi$

Substitute the value of r

$C''(2.09)=\frac{16}{(2.09)^3}+0.28\pi=2.63>0$

Therefore,the product cost is minimum at r=2.09

h= $\frac{200}{\pi (2.09)^2}=14.57$

Radius of can,r=2.09 cm

Height of cone,h=14.57 cm

4 0

2 years ago

Find m<adc.please dhdhdhd

Alexus [3.1K]

They both are complementary angles i.e their sum must equals 90°

4x+ 31 + 6x + 39 = 90
10x + 70 = 90
10x = 90-70
10x = 20
x = 2

we have to find angle ADC
just put the value of x in that expression for that angle.

angle ADC = 6x + 39 = 6 (2)+39 = 12 + 39 = 51°

4 0

2 years ago