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anzhelika [568]
3 years ago
6

A simple random sample of 85 is drawn from a normally distributed population, and the mean is found to be 146, with a standard d

eviation of 34. Which of the following values is outside the 99% confidence interval for the population mean? Use the table below to help you answer the question.
Remember, the margin of error, ME, can be determined using the formula mc026-1.jpg.
a) the value of 135 because it is not greater than 136.5
b) the value of 137 because it is greater than 136.5
c) the value of 138 because it is less than 153.2
d) the value of 154 because it is greater than 153.2
Mathematics
2 answers:
goldfiish [28.3K]3 years ago
6 0
The correct answer is a. the value of 35 because it is not greater than 136.5
bogdanovich [222]3 years ago
5 0

Answer:

a) the value of 135 because it is not greater than 136.5

Step-by-step explanation:

Given that

n = sample size =85

Mean = 146

std dev =34

Std error of sample = 34/sqrt 85

= 3.6878

99% z critical value = 2.58

Margin of error = ±9.515

Confidence interval lower bound = 146-9.515 = 136.485

                                 Upper bound = 146+9.515 =155.515

Hence we find that 135 is less than lower bound, hence 135 does not lie within 99% confidence interval

a) the value of 135 because it is not greater than 136.5

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777dan777 [17]
The answer is 30 because i had this on a test
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3 years ago
Find the equation of the line parallel to y=2x+6 passing through (4,5)
ozzi

Answer:

y=2x-3

when two lines are parallel, they have the same slope.

in the formula y=mx+b, m=slope of the line

we know 2 will be the slope for the line passing through (4,5)

next plug in (4,5) into the formula with 2 as the slope

4=x 5=y

next 5=2(4)+b

and you end up with

y=2x-3 when you simplify

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If the lateral area of a right rectangular prism is 384 cm^2, its length twice its width, and its height is twice its length, fi
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Width = w
Length = 2w
Height = 4w
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Hope this helps. - M
7 0
4 years ago
3.) mr. smith’s class sold wrapping paper for $3.50 each and mr. davis’ class sold magazines for $2.75 each. together, the class
igor_vitrenko [27]

Answer:

The number of wrapping paper sold was 32 and the number of magazines sold was 40

Step-by-step explanation:

Let

x ----> the number of wrapping paper sold

y ----> the number of magazines sold

we know that

The classes sold 72 items

so

x+y=72 ----> equation A

The classes earned $222 for their school

so

3.50x+2.75y=222 ----> equation B

Solve the system of equations by graphing

Remember that the solution of the system of equations is the intersection point both graphs

using a graphing tool

The solution is (32,40)

see the attached figure

therefore

The number of wrapping paper sold was 32 and the number of magazines sold was 40

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4 years ago
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