We are asked to solve for the zeros of the given quadratic equation f(x) = 9x2 + 6x + 1. To solve this, first, we need to set the given equation into zero such as the succeeding solution is shown below: 0 = 9x2 + 6x +1 Perform factoring such as: 0 = (3x + 1) (3x + 1) Solving for x1, we have: 3x + 1=0 3x = -1 x1 = -1/3 Soving for x2, we have: 3x +1=0 x = -1/3 Therefore, the zeroes of the given expression is both -1/3 for x1 and x2.
