Answer:

Step-by-step explanation:
Given that:
The number of observations is:
6, 10, 12
If we are to use a simple random sampling without replacement, then we will have:
(6,10) (6,12) (10,12)
Here;
the sample size n = 2
The population size N = 3
For (6,10) ; The sample mean = 
= 
= 8
For (6,12) ; The sample mean = 
= 
= 9
For (10, 12) ; The sample mean = 
= 
= 11
The probability distribution of sample mean(x) is:
X 8 9 11
P(X=x)

Thus, the probability that the sample mean is larger than 8 is:
P(X> 8) = P(X = 9) + P(X + 11)
P(X> 8) = 
P(X > 8) = 
P(X> 8) = 
Answer:
See below
Step-by-step explanation:
3*7
3(3+4)
3*3 + 3*4
9 + 12
21
Hello,
2 cases:
if 1/3*q-5>0 then
|1/3*q-5|=1/3*q-5
1-|1/3*q-5|=-6
1-(1/3*q-5)=-6
1-1/3*q+5=-6
6-1/3*q=-6
-1/3*q=-12
q=36
else
|1/3*q-5|=-(1/3*q-5)
1-|1/3*q-5|=-6
1+(1/3*q-5)=-6
1+1/3*q-5=-6
-4+1/3*q=-6
1/3*q=-2
q=-6
The first one
the first 2 numbers gives a power of 1 then the second gives you 1-4.
1+1-4 is -2 so its the first one