Question

How many gallons of paint are needed to paint the walls of a rectangular​ prism-shaped room that is 18 ft by 10 ft and 8 ft high if 1 gallon of paint covers 40 sq​ ft? Assume there are no doors or windows.

Answer 1

Answer:

11.2 gallons.

Step-by-step explanation:

We have been given that a rectangular​ prism-shaped room is 18 ft by 10 ft and 8 ft high. We are asked to find the gallons of paint needed to paint the walls of room.    

First of all, we will find area of walls, we need to paint.

2 walls would be $18\text{ ft}\times 8\text{ ft}$

2 walls would be $10\text{ ft}\times 8\text{ ft}$

$\text{Total area of walls}=2(18\text{ ft}\times 8\text{ ft}+10\text{ ft}\times 8\text{ ft})$

$\text{Total area of walls}=2(144\text{ ft}^2+80\text{ ft}^2)$

$\text{Total area of walls}=2(224\text{ ft}^2)$

$\text{Total area of walls}=448\text{ ft}^2$

We have been given that 1 gallon of paint covers 40 sq​ ft. To find the gallons of paint needed, we will divide total area by 40.

$\text{Gallons of paint needed}=\frac{448}{40}$

$\text{Gallons of paint needed}=11.2$

Therefore, 11.2 gallons of paint are needed to paint the walls.