3 years ago

What's the scope internet form of the linear equation: 2x-8y=32 ?

Mathematics

1 answer:

Shtirlitz [24]3 years ago

6 0

The slope INTERCEPT form is y=.25x-4

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HELP PLEASE!!!!!!! IM TIREDD AND AM STUCK ON THIS LAST QUESTION THAT IVE BEEN WORKIGN ON FOR 20 MINUTES

avanturin [10]

Answer:

1/3

Step-by-step explanation:

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3 years ago

Minnie went to Orlando Bank to get a student loan. She borrowed $700 at a 12% interest rate compounded annually over 2 years. Ho

Sonbull [250]

Answer:

she have to pay rs.168 at the end of two years

8 0

2 years ago

Whats the slope of (-8,-1) and (-6,-2)

STatiana [176]

Answer: -1/2 or -0.5.
Explanation: -2- -1, -6- -2= -0.5

5 0

2 years ago

Jacob is asked to solve the follow problem: "Kayla is 9 years older than twice Hannah’s age. If the difference in their ages is

tatiyna

Answer:

Step-by-step explanation:

k = 2h+9

h+16=k

h+16=2h+9

-h = -7

h = 7

hannah is 7 and kayla is 23

jacob is wrong because if u do 16*2+7 it’s 39 and 39-16 does not equal 16

6 0

2 years ago

The numbers of regular season wins for 10 football teams in a given season are given below. Determine the range, mean, variance,

tensa zangetsu [6.8K]

We have the following data set:

2,7,15,3,12,9,15,8,3,10

The range is the difference between the highest and lowest values in the set, to find the range, order the data set from least to greatest.

2,3,3,7,8,9,10,12,15,15

Then,

$\begin{gathered} \text{Range}=15-2 \\ \text{Range}=13 \end{gathered}$

Mean is represented by the following expression:

$\text{Mean}=\frac{\text{Sum of all data points}}{Number\text{ of data po}ints}$ $\text{Mean}=\frac{84}{10}=8.4$

Population variance formula looks like this:

$\begin{gathered} \sigma^2=\frac{\sum^{}_{}(x-\mu)^2}{N} \\ \text{where,} \\ \sigma^2=\text{population variance} \\ \sum ^{}_{}=addition\text{ of} \\ x=\text{each value} \\ \mu=population\text{ mean} \\ N=\text{ number of values in the population} \end{gathered}$

Then, substituting:

$\begin{gathered} \sigma^2=\frac{(2-14)^2+(3-14)^2+\cdots+(15-14)^2}{10} \\ \sigma^2=20.44 \end{gathered}$

For the standard deviation:

$\begin{gathered} s=\sqrt[]{\frac{\sum ^{}_{}(x-\mu)^2}{N}} \\ s=4.521 \end{gathered}$

5 0

1 year ago