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3 years ago

Please help 1 through 3

Mathematics

1 answer:

Wewaii [24]3 years ago

7 0

Answer:

object is moving to the right with constant speed
object is moving to the left with constant speed
object was stationary for a while, then started moving to the right with constant speed

Step-by-step explanation:

These graphs are of position, so the slope of the graph is the change of position with time, which is velocity. When the slope is positive, the velocity is positive, meaning its direction is to the right. When the slope is negative, the velocity is negative, meaning its direction is to the left.

When the slope is zero, the object is stationary (not moving). The position remains as it was.

1. The position vs. time curve is a straight line with positive slope. The object is moving to the right with constant velocity.

2. The position vs. time curve is a straight line with negative slope. The object is moving to the left with constant velocity.

3. The position vs. time curve is flat for a while, then increasing with constant slope. The object stayed where it was for a while, then began moving to the right (to larger values of x) with constant velocity.

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denis23 [38]

Answer:

n > 3

Step-by-step explanation:

isolate n on the left side by subtracting 8 from both sides

n > 3

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3 years ago

Find a vector equation and parametric equations for the line through the point (7,4, 5) and parallel to the vector 3i 2j-k .

aleksley [76]

Answer: vector equation r = (7+3t)i + (4+2t)j + (5 - 5t)k

parametric equations: x = 7 + 3t; y = 4 + 2t; z = 5 - 5t

Step-by-step explanation: The vector equation is a line of the form:

r = $r_{0}$ + t.v

where

$r_{0}$ is the position vector;

v is the vector;

For point (7,4,5):

$r_{0}$ = 7i + 4j + 5k

Then, the equation is:

r = 7i + 4j + 5k + t(3i + 2j - k)

r = (7 + 3t)i + (4 + 2t)j + (5 - 5t)k

The parametric equations of the line are of the form:

x = $x_{0}$ + at

y = $y_{0}$ + bt

z = $z_{0}$ + ct

So, the parametric equations are:

x = 7 + 3t

y = 4 + 2t

z = 5 - 5t

4 0

3 years ago

In order to estimate the height of a building, two students stand at a certain distance from the building at street level. from

enyata [817]

Let h represent the height of the building. Then the difference between the two angle measurement locations is
.. h/tan(39°) -h/tan(50°) = 300 ft
.. h = (300 ft)/(1/tan(39°) -1/tan(50°))
.. h ≈ 758 ft

The height of the building is about 758 feet.

4 0

3 years ago

50 Points:

Bond [772]

The answer to this would be C because you can multiply everything by 3 and still have a consistent-dependent system.

6 0

3 years ago

The inequality log8(2x) < log2(x – 2) can be graphed on the graphing calculator by using the inequalities log8(2x) < y and

denis-greek [22]

Answer:

c - (4, ∞)

Step-by-step explanation:

answer on edg

4 0

3 years ago

Please help 1 through 3​

Please help 1 through 3