All categories

3 years ago

Please help 1 through 3

Mathematics

1 answer:

Wewaii [24]3 years ago

7 0

Answer:

object is moving to the right with constant speed
object is moving to the left with constant speed
object was stationary for a while, then started moving to the right with constant speed

Step-by-step explanation:

These graphs are of position, so the slope of the graph is the change of position with time, which is velocity. When the slope is positive, the velocity is positive, meaning its direction is to the right. When the slope is negative, the velocity is negative, meaning its direction is to the left.

When the slope is zero, the object is stationary (not moving). The position remains as it was.

1. The position vs. time curve is a straight line with positive slope. The object is moving to the right with constant velocity.

2. The position vs. time curve is a straight line with negative slope. The object is moving to the left with constant velocity.

3. The position vs. time curve is flat for a while, then increasing with constant slope. The object stayed where it was for a while, then began moving to the right (to larger values of x) with constant velocity.

You might be interested in

I need the answer please

lutik1710 [3]

5 inches : 2 feet

÷2.5

120 inches : 48 feet

÷2.5

answer: 48 feet

4 0

3 years ago

Neeed helpppp asppp I ready math

nikitadnepr [17]

Answer:

D because we just distribute the 0.5

Hope this helps and brainliest please

6 0

3 years ago

Read 2 more answers

Can anyone answer this?

Tema [17]

Answer:

B. Im pretty sure

Step-by-step explanation:

7 0

3 years ago

What is the value of b that makes the lines, given by 3x-y=4 and 2y+4bx=1, perpendicular?

USPshnik [31]

b = 1/6

Explanation:

3x-y=4 ...1st equation

Rewriting in slope- intercept form:

y = 3x - 4

2y+4bx=1

Rewriting in slope- intercept form:

2y = -4bx + 1

y = -4bx/2 + 1/2

Equation of line: y = mx + c

where m = slope, c = intercept

For a line to be perpendicular to another, the slope of one will be the negative reciprocal of the slope of another.

Slope of the 1st equation = 3

m = 3

reciprocal of 3 = 1/3

negative reciprocal of 3 = -1/3

Slope of the 2nd equation = -4b/2

we equate both slope:

negative reciprocal of 3 = -4b/2

-1/3 = -4b/2

cross multiply:

-1(2) = 3(-4b)

-2 = -12b

Divide both sides by -12:

-2/-12 = -12b/-12

b = 1/6

Hence, the value of b that makes the lines perpendicular is 1/6

6 0

1 year ago

What are the missing coordinates? My teacher said it was (h-m,n), but I’m saying it is (h+m,n). Could anyone help? (16 points)

Afina-wow [57]

The missing coordinates of the parallelogram is (m + h, n).

Solution:

Property of parallelogram,

<em>Diagonals of the parallelogram bisect each other.</em>

Solve using mid-point formula:

$$\text{Midpoint} =\left( \frac{x_1+x_2}{2}, \frac{y_1+y_2}{2}\right )$

Here $x_1=m, y_1=n, x_2=h, y_2=0$

$$=\left( \frac{m+h}{2}, \frac{n+0}{2}\right )$

$$\text{Midpoint} =\left( \frac{m+h}{2}, \frac{n}{2}\right )$

<u>To find the missing coordinate:</u>

Let the missing coordinates by x and y.

Here $x_1=0, y_1=0, x_2=x, y_2=y$

$$\text{Midpoint}=\left( \frac{0+x}{2}, \frac{0+y}{2}\right )$

$$\left( \frac{m+h}{2}, \frac{n}{2}\right )=\left( \frac{0+x}{2}, \frac{0+y}{2}\right )$

$$\left( \frac{m+h}{2}, \frac{n}{2}\right )=\left( \frac{x}{2}, \frac{y}{2}\right )$

Now equate the x-coordinate.

$$ \frac{m+h}{2}=\frac{x}{2}$

Multiply by 2 on both sides of the equation, we get

x = m + h

Now equate the y-coordinate.

$$\frac{n}{2} = \frac{y}{2}$

Multiply by 2 on both sides of the equation, we get

y = n

The coordinates are (m+h, n).

Hence the missing coordinates of the parallelogram is (m + h, n).

5 0

4 years ago

Please help 1 through 3​

Please help 1 through 3