I^3=-i
therefor -27i=(3i)^3
so we can get a sum of 2 perfect cubes
a^3+b^3=(a+b)(a^2-ab+b^2)
so
remember that i²=-1
x^3+(3i)^3=(x+3i)(x²-3xi-1)
Answer:
42592
Step-by-step explanation:
Answer: (7, 0)
Step-by-step explanation:
We have the system of equations:
9*x - y = 63
x = y + 7
We can see that the "x" is isolated in the second equation, then we can replace it in the first equation to get:
9*x - y = 63
9*(y + 7) - y = 63
Now we have an equation that only depends on one variable, so we can solve it:
9*y + 63 - y = 63
8*y + 63 = 63
8*y = 63 - 63 = 0
y = 0/8 = 0.
Now we know the value of y, we can replace this in one of the initial equations to find the value of x, i will replace this in the second equation:
x = y + 7 = 0 + 7 = 7
Then the point that is a solution for the system of equations is (7, 0)
Answer:
x = 
Step-by-step explanation:
Given
3x + 2 = 6 ( subtract 2 from both sides )
3x = 4 ( divide both sides by 3 )
x = 
In the equation

you would be solving linear equations to find the answer to a question