You can't change more than 100 percent
C=pid
Since d=9m and pi=3.142, C=3.142*9m=28.278
Rounded to 1 decimal point =28.3
Answer: The required fraction = ![\dfrac18](https://tex.z-dn.net/?f=%5Cdfrac18)
Step-by-step explanation:
Let the required fraction = ![\dfrac{p}{q}](https://tex.z-dn.net/?f=%5Cdfrac%7Bp%7D%7Bq%7D)
Given: Initial height = 192 inches
Height of ball after second bounce = ![\dfrac{p}{q}\times192](https://tex.z-dn.net/?f=%5Cdfrac%7Bp%7D%7Bq%7D%5Ctimes192)
Height of ball after third bounce = ![\dfrac{p}{q}\times\dfrac{p}{q}\times192=192\dfrac{p^2}{q^2}](https://tex.z-dn.net/?f=%5Cdfrac%7Bp%7D%7Bq%7D%5Ctimes%5Cdfrac%7Bp%7D%7Bq%7D%5Ctimes192%3D192%5Cdfrac%7Bp%5E2%7D%7Bq%5E2%7D)
After the third bounce it is 3 inches off the ground.
So,
![(\dfrac{p}{q})^2192=3\\\\\\(\dfrac{p}{q})^2=\dfrac{3}{192}\\\\(\dfrac{p}{q})^2=\dfrac{1}{64}\\\\(\dfrac{p}{q})^2=(\dfrac{1}{8})^2\\\\ \dfrac{p}{q}=\dfrac{1}{8}](https://tex.z-dn.net/?f=%28%5Cdfrac%7Bp%7D%7Bq%7D%29%5E2192%3D3%5C%5C%5C%5C%5C%5C%28%5Cdfrac%7Bp%7D%7Bq%7D%29%5E2%3D%5Cdfrac%7B3%7D%7B192%7D%5C%5C%5C%5C%28%5Cdfrac%7Bp%7D%7Bq%7D%29%5E2%3D%5Cdfrac%7B1%7D%7B64%7D%5C%5C%5C%5C%28%5Cdfrac%7Bp%7D%7Bq%7D%29%5E2%3D%28%5Cdfrac%7B1%7D%7B8%7D%29%5E2%5C%5C%5C%5C%20%5Cdfrac%7Bp%7D%7Bq%7D%3D%5Cdfrac%7B1%7D%7B8%7D)
Hence, The required fraction = ![\dfrac18](https://tex.z-dn.net/?f=%5Cdfrac18)
Answer:
B) Hundreds
Step-by-step explanation:
<em>2380 ÷ 10 = 238</em>
The number 238 is in the hundreds as the first digit is in the hundreds. You can tell because you say "two hundred."
Hope this helps
Meter is 0.5 and the fraction is I think 1/2