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Anuta_ua [19.1K]
3 years ago
10

I need math help please

Mathematics
1 answer:
Misha Larkins [42]3 years ago
6 0
\left(a^4b^{ \frac{1}{2} } \right)^4 \sqrt[6]{b^6}=a^{4\cdot4} \ b^{ \frac{1}{2}\cdot4 } \ b^{ \frac{6}{6} }=a^{16} \ b^{2} \ b^{1}=a^{16}b^3
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Find 3 consecutive odd integers such that the sum of the smallest number and the middle number is 27 less than 3 times the large
Mandarinka [93]

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3 years ago
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