A rhombus has perimeter 120 M and one of its diagonal is 50 M find the area of the Rhombus
1 answer:
The area of the rhombus is 829.1562m².
<h3>What is the area of the rhombus?</h3>A rhombus is a four sides quadrilateral with the four sides equal in length
The area of a rhombus = ×√(p² - 4d²)
where p is the perimeter and d is the diagonal
1/4(50) x √(120² - 4 x 50²) =829.1562m²
To learn more about a rhombus, please check: brainly.com/question/22825947
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Answer:
Step-by-step explanation:
Let represent the length of the rectangle. The width can be represented as
.
The perimeter of a rectangle with lengths and
is given by
.
Thus, we have:
The width is then .