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garik1379 [7]
2 years ago
6

Tell whether the equation has the ordered pair as a solution y=6x; (-7,-42)

Mathematics
1 answer:
Ber [7]2 years ago
3 0

Answer:

Yes

Step-by-step explanation:

Substituting in x = -7, we get y = 6(-7) = -42, which is the same as the y coordinate of the given point.

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W + 1 = d and d = 3w solve by substitution
STALIN [3.7K]

Answer:

Step-by-step explanation:

Given

w + 1 = d...........equation 1

d = 3w ...............equation 2

Now putting d = 3w in equation 1

w + 1 = 3w

3w - w = 1

2w = 1

w = 1 / 2

putting w = 1 / 2 in equation 2

d = 1 / 2 * 3

 = 3/2

Hope it helps :)

8 0
3 years ago
Read 2 more answers
Solve the inequality r-(-5)>-2
Jet001 [13]

Answer:

r>-7

Step-by-step explanation:

Solving an inequality is similar to solving an equation. To solve for r, isolate it. Whatever you do to one side, do to the other. Remember that a negative and a negative equal a positive, thus one side of the inequality becomes r + 5. Then, subtract both sides by -5 to find the answer.

r-(-5) >-2\\r+5>-2\\r>-7

7 0
3 years ago
Find GCF of 40 and 120​
vagabundo [1.1K]

Answer:

Hi there!

<h2>Find the GCF of 40 and 120</h2>

  • The GCF of 40 and 120 is 40

40 ÷ 40 = 1

120 ÷ 40 = 3

<h3>Hope its help!</h3>
5 0
3 years ago
Cos(0.5)+cos(0.5+2(3.14159265))+cos(0.5+4(3.14159265))
aleksandr82 [10.1K]

Answer:

2.63274768567

Step-by-step explanation:

First, note that 3.1415... is p, so 2(3.1415...) is 2pi and 4(3.1415...) is 4pi.

2pi and 4pi are full rotations, which will lead to the same cosine (i.e. cos(x) = cos (x+2pi) = cos(x+4pi) = ... = cos (x+2k*pi)).

So, the expression equals cos0.5 + cos 0.5 + cos0.5 = 3cos0.5 = 3(0.87758256189) = 2.63274768567

I hope this helps! :)

7 0
3 years ago
A function f (x) = √ x is transformed into the function
Brilliant_brown [7]

Answer:

a) vertical translation: up five units

b) horizontal translation: right 2 units

c) vertically stretched by 3 units

Step-by-step explanation:

https://www.humbleisd.net/cms/lib2/TX01001414/Centricity/Domain/3611/Square%20Root%20Graphs%202015.pdf

8 0
3 years ago
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