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garik1379 [7]
2 years ago
6

Tell whether the equation has the ordered pair as a solution y=6x; (-7,-42)

Mathematics
1 answer:
Ber [7]2 years ago
3 0

Answer:

Yes

Step-by-step explanation:

Substituting in x = -7, we get y = 6(-7) = -42, which is the same as the y coordinate of the given point.

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Please help me with this problem immediately
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Step-by-step explanation:

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3 years ago
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Find maclaurin series
Mumz [18]

Recall the Maclaurin expansion for cos(x), valid for all real x :

\displaystyle \cos(x) = \sum_{n=0}^\infty (-1)^n \frac{x^{2n}}{(2n)!}

Then replacing x with √5 x (I'm assuming you mean √5 times x, and not √(5x)) gives

\displaystyle \cos\left(\sqrt 5\,x\right) = \sum_{n=0}^\infty (-1)^n \frac{\left(\sqrt5\,x\right)^{2n}}{(2n)!} = \sum_{n=0}^\infty (-5)^n \frac{x^{2n}}{(2n)!}

The first 3 terms of the series are

\cos\left(\sqrt5\,x\right) \approx 1 - \dfrac{5x^2}2 + \dfrac{25x^4}{24}

and the general n-th term is as shown in the series.

In case you did mean cos(√(5x)), we would instead end up with

\displaystyle \cos\left(\sqrt{5x}\right) = \sum_{n=0}^\infty (-1)^n \frac{\left(\sqrt{5x}\right)^{2n}}{(2n)!} = \sum_{n=0}^\infty (-5)^n \frac{x^n}{(2n)!}

which amounts to replacing the x with √x in the expansion of cos(√5 x) :

\cos\left(\sqrt{5x}\right) \approx 1 - \dfrac{5x}2 + \dfrac{25x^2}{24}

7 0
2 years ago
Given the zeros 7, -1, 9 what are the factors
MrRissso [65]
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4 0
3 years ago
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PtichkaEL [24]

Answer:

10 ( b+10)

Step-by-step explanation:

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hope it helps !!!!

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Answer:

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Step-by-step explanation:

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10÷80*100= 12.5%

all this together is 100%

meaning the best answer is

Q is the only place that = -1/2

3 0
3 years ago
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