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DaniilM [7]
3 years ago
10

11 1/2 and 13 3/4 is?

Mathematics
1 answer:
Tpy6a [65]3 years ago
5 0
This would depend on what you are asking for.

If you are adding the two numbers(which the word and is implying) you’re answer is 25 1/4.

You get this by finding a common denominator. In this case, that can be 4.

Turn 1/2 in to 2/4.

Next, you add 11 and 13 to get 24.

Then, you’ll add 2/4 and 3/4. You will get 1 1/4

Add 24 and 1 1/4. You have your answer of 25 1/4
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A neon light flashes five times every 10 seconds. Show that the light flashes 43 200 times in one day.
11Alexandr11 [23.1K]

1 day = 24 hours

1 hour = 60 minutes

1 minute = 60 seconds

60 seconds x 60 minutes = 3,600 seconds per hour

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4 0
2 years ago
What is the distance between 4-i and -2+3i?
stepan [7]
If you're working with complex numbers, then I'm sure you're comfortable with plotting them on a complex-plane ... real part of the number along the x-axis, and imaginary part of the number along the y-axis.

When you look at it that way, your two points are simply two points on the x-y plane:

           4 - i    ===>  (4, -1)

         -2 + 3i  ===>  (-2, 3) .

The distance between them is

                       D  =  √ (difference in 'x')² + (difference in 'y')²

                           =  √  (6)² + (4)²

                           =  √ (36 + 16)

                           =   √ (52)

                           =      7.211  (rounded)   
4 0
3 years ago
Write the given second order equation as its equivalent system of first order equations. u′′−5u′−4u=1.5sin(3t),u(1)=1,u′(1)=2.5
lakkis [162]

Answer:

hi your question options is not available but attached to the answer is a complete question with the question options that you seek answer to

Answer:  v = 5v + 4u + 1.5sin(3t),

  • 0
  • 1
  •  4
  • 5
  • 0
  • 1.5sin(3t)
  • 1
  •  2.5

Step-by-step explanation:

u" - 5u' - 4u = 1.5sin(3t)        where u'(1) = 2.5   u(1) = 1

v represents the "velocity function"   i.e   v = u'(t)

As v = u'(t)

<em>u' = v</em>

since <em>u' = v </em>

v' = u"

v'  = 5u' + 4u + 1.5sin(3t)   ( given that u" - 5u' - 4u = 1.5sin(3t) )

    = 5v + 4u + 1.5sin(3t)  ( noting that v = u' )

so v' = 5v + 4u + 1.5sin(3t)

d/dt \left[\begin{array}{ccc}u&\\v&\\\end{array}\right]= \left[\begin{array}{ccc}0&1&\\4&5&\\\end{array}\right]  \left[\begin{array}{ccc}u&\\v&\\\end{array}\right] + \left[\begin{array}{ccc}0&\\1.5sin(3t)&\\\end{array}\right]

Given that u(1) = 1 and u'(1) = 2.5

since v = u'

v(1) = 2.5

note: the initial value for the vector valued function is given as

\left[\begin{array}{ccc}u(1)&\\v(1)\\\end{array}\right]  = \left[\begin{array}{ccc}1\\2.5\\\end{array}\right]

7 0
3 years ago
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