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3 years ago

Graph the equation y = 1/8x-7

Mathematics

2 answers:

laila [671]3 years ago

8 0

Answer:

$slope:1/8y-intercept:-7\\COORDINATES(x,-7)\\\\(56,0)$

Step-by-step explanation:

Brut [27]3 years ago

3 0

Use the equation y=mx+b
B is the y intercept
So put (0, -7) and from there go up 1 over 8

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At 6,000 calories a day, a person with genotype X will weigh 285 lbs with much energy and high cholesterol levels. At 3,500 calo

kkurt [141]

Answer: norm of reaction

Step-by-step explanation:

norm of a reaction which is the capacity of a genotype to produce different phenotypes in response to the environment. The group of phenotypic expressions under different environmental conditions. A organism can own all the genetic complements necessary to fully development. However, if there is no suitable nutricion, the development does not occur. The environment only changes the phenotypic characteristics within certain limits ruled by the genotype (norm of reaction). The genotype do not determine a phenotypes, but a amount of possible phenotypes, a norm of reaction. A certain phenotype will materialize itself depending on the interaction of a certain genotype with the environment.

6 0

3 years ago

45(15x+20)−7x=56(12x−24)+6 Enter your answer in the box.

zzz [600]

X=1119/2 hope this helps :)

3 0

3 years ago

How much difference do a couple of weeks make for birth weight? Late-preterm babies are born with 34 to 36 completed weeks of ge

stiks02 [169]

Answer:

a) 0.3277

b) 0.0128

Step-by-step explanation:

We are given the following information in the question:

N(2750, 560).

Mean, μ = 2750

Standard Deviation, σ = 560

We are given that the distribution of distribution of birth weights is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

a) P (less than 2500 grams)

P(x < 2500)

$P( x < 2500) = P( z < \displaystyle\frac{2500 - 2750}{560}) = P(z < -0.4464)$

Calculation the value from standard normal z table, we have,

$P(x < 2500) = P(z < -0.4464) = 0.3277 = 32.77\%$

b) P ((less than 1500 grams)

P(x < 1500)

$P( x < 1500) = P( z < \displaystyle\frac{1500 - 2750}{560}) = P(z < -2.2321)$

Calculation the value from standard normal z table, we have,

$P(x < 1500) = P(z < -2.2321) = 0.0128 = 1.28\%$

3 0

2 years ago

Just number 4 pleaseeee

Aleksandr [31]

Hello!

The formula is given to you. :)

C = 3.14 • D (diameter; line across a circle that cuts it in half)

C = 3.14 • 21 = 65.94 inches.

Hope I helped! Also, I hope I didn’t answer this too late. ;)

~Destiny ^_^

7 0

3 years ago

SAT scores are normed so that, in any year, the mean of the verbal or math test should be 500 and the standard deviation 100. as

vovangra [49]

Answer:

a) $P(X>625)=P(\frac{X-\mu}{\sigma}>\frac{625-\mu}{\sigma})=P(Z>\frac{625-500}{100})=P(Z>1.25)$

$P(Z>1.25)=1-P(Z$

b) $P(400$

$P(-1$

c) $z=-0.842$

And if we solve for a we got

$a=500 -0.842*100=415.8$

So the value of height that separates the bottom 20% of data from the top 80% is 415.8.

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Part a

Let X the random variable that represent the SAT scores of a population, and for this case we know the distribution for X is given by:

$X \sim N(500,100)$

Where $\mu=500$ and $\sigma=100$

We are interested on this probability

$P(X>625)$

And the best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\sigma}$

If we apply this formula to our probability we got this:

$P(X>625)=P(\frac{X-\mu}{\sigma}>\frac{625-\mu}{\sigma})=P(Z>\frac{625-500}{100})=P(Z>1.25)$

And we can find this probability using the complement rule and with the normal standard table or excel:

$P(Z>1.25)=1-P(Z$

Part b

We are interested on this probability

$P(400$

And the best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\sigma}$

If we apply this formula to our probability we got this:

$P(400$

And we can find this probability with this difference:

$P(-1$

And in order to find these probabilities we can find tables for the normal standard distribution, excel or a calculator.

$P(-1$

Part c

For this part we want to find a value a, such that we satisfy this condition:

$P(X>a)=0.8$ (a)

$P(X$ (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.

As we can see on the figure attached the z value that satisfy the condition with 0.2 of the area on the left and 0.8 of the area on the right it's z=-0.842. On this case P(Z<-0.842)=0.2 and P(Z>-0.842)=0.8

If we use condition (b) from previous we have this:

$P(X$

$P(z$

But we know which value of z satisfy the previous equation so then we can do this:

$z=-0.842$

And if we solve for a we got

$a=500 -0.842*100=415.8$

So the value of height that separates the bottom 20% of data from the top 80% is 415.8.

8 0

2 years ago