If (9^2)^p = 9^8, what is the value of p? A. 2 B. 3 C. 4 D. 6
2 answers:
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Answer: 3. 4 4.
Step-by-step explanation:
8^2 + 12^3 = c^2
64 + 144 = c^2
208 = c^2
√208
The final answer is the square root of 208
8^2 + b^2 = 17^2
64 + b^2 = 289
-64 64
b^2 = 225
Answer:
C. $5180
Step-by-step explanation:
To solve this question, we have to understand the normal probability distribution and the central limit theorem.
Normal probability distribution:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
Z-scores lower than -2 or higher than 2 are considered unusual.
Central limit theorem:
The Central Limit Theorem estabilishes that, for a random normally distributed variable X, with mean and standard deviation
, the sample means with size n can be approximated to a normal distribution with mean
and standard deviation
In this problem, we have that:
Which of the following mean costs would be considered unusual?
We have to find the z-score for each of them
A. $6350
By the Central Limit Theorem
Not unusual
B. $6180
Not unusual
C. $5180
Unusual, and this is the answer.