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Mazyrski [523]
3 years ago
11

What is the verb used to determine the number of, or amount of, something?

Mathematics
1 answer:
kirza4 [7]3 years ago
4 0
Calculate. Good luck in scramble with friends.
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Need help this question
shutvik [7]
There are 7 more tan puppies. ( Just subtract 15 and 8 )
7 0
4 years ago
Read 2 more answers
Solve the equation for m:<br><br> m/5 = 60
alex41 [277]

Answer:

m = 300

Step-by-step explanation:

m/5 = 60

multiply both sides of the equation by 5

m = 60 * 5 = 300

3 0
3 years ago
Read 2 more answers
Help please ! A B Or C
malfutka [58]

Answer:

B) 46

Step-by-step explanation:

What you have to do here is plug in the numbers 2, 3, 4, and 5 in for i in the equation and then add the sums together:

3(2) + 1 = 7

3(3) + 1 = 10

3(4) + 1 = 13

3(5) + 1 = 16

Add those together and they equal 46

3 0
3 years ago
Interpret (1,15)<br><br> interpret (4,60)
statuscvo [17]

Interpreting (1,15) with (4,60), found that (4,60) is 4 times of the coordinate (1,15).

<h3>What are coordinates?</h3>

A pair of numbers that describe the position of a point on a coordinate plane by using the horizontal and vertical distances from the two reference axes.

For interpreting we have to find the relation between (1,15) and (4,60)

We have, (1,15)

For x- coordinate 1, y- coordinate will be 15

Now,

let us take x- coordinate=2 then y- coordinate =30

again, if x-coordinate = 3 then y-coordinate  = 45

lastly, if the x-coordinate =4 then y-coordinate = 60

That means (4,60) is the 4 times of the coordinate (1,15) i.e., the x-coordinate is 4 times as well as the y- coordinate is 4 times.

Learn more about coordinates here:

brainly.com/question/23450276

#SPJ1

4 0
2 years ago
PLS help me with thisss:((((((​
lara31 [8.8K]

Answer:

C and B

Step-by-step explanation:

(6)

\frac{3x-7y}{8} × \frac{6}{3x-7y} ← cancel 3x - 7y on numerator and denominator

= \frac{1}{8} × \frac{6}{1} = \frac{6}{8} = \frac{3}{4} → C

(7)

\frac{6x}{x^2-9} ÷ \frac{8}{4x-12}

Factorise the denominators of both fractions

x² - 9 = x² - 3² = (x - 3)(x + 3) ← difference of squares

4x - 12 ← factor out 4 from each term

= 4(x - 3)

Then rewrite as

\frac{6x}{(x-3)(x+3)} ÷ \frac{8}{4(x-3)} ← cancel 8 and 4 by 4

= \frac{6x}{(x-3)(x+3)} ÷ \frac{2}{x-3}

• leave first fraction, change ÷ to × , turn second fraction ' upside down'

= \frac{6x}{(x-3)(x+3)} × \frac{x-3}{2} ← cancel x - 3 on numerator and denominator

= \frac{6x}{x+3} × \frac{1}{2} ← cancel 2 and 6 on numerator and denominator

= \frac{3x}{x+3} → B

8 0
3 years ago
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