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3 years ago

I really need help

1 answer:

6 0

The answer should be
(x-10)²+(y+4)²=16

The equation of any circle is
(x – h)² + (y – k)² = r²

(h,k) is the center point and r is the radius

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Please help me with #4 i really need it?

Alexandra [31]

Okay so for the similar two, draw one smaller and one bigger and then draw one that is completely different, but still a right triangle. Then explain how each triangle is different. I hope I helped! :)

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4 years ago

What are the values of a and b?

Drupady [299]

Step-by-step explanation:

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3 years ago

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Correct answer gets 5 stars and brainliest

Katena32 [7]

Answer:

Step-by-step explanation:

C(3 , -2) & D (7, -8)

Distance = $\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$

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3 years ago

Solve for x. x² = 144

Akimi4 [234]

Answer:

x = 12

Step-by-step explanation:

if ,

$x {}^{2} = 144$

then,

$x \: = \sqrt{144}$

hence,

$x \: = 12$

i hope you got it.

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3 years ago

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Click on the graph to choose the correct answer to the equation. 3x - y ≥ 5 hurry

mr_godi [17]

For this case we have:

To begin we must graph $3x-y = 5$ , for this:

We do $x = 0$ , then:

$3 (0) -y = 5\\-y = 5\\y = -5$

So, we have the point $(x_ {1}, y_ {1}) = (0, -5)$

We do $y = 0$ , then:

$3x-0 = 5\\3x = 5$

$x = \frac {5} {3}$

So, we have the point $(x_ {2}, y_ {2}) = (\frac {5} {3}, 0)$

We place both points in a coordinate plane and graph the line. Now, we must find the shaded region that identifies the inequality $3x-y\geq 5$

We must replace any point located to the left or to the right of the line. If the inequality is met, then the shaded region will be on the respective side.

We substitute the point $(x_ {3}, y_ {3}) = (5,0)$

$3 (5) -0\geq5 \\15\geq5$

The inequality is met, then the shaded region is to the right of the line.

Answer:

See attached image

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4 years ago

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