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Masja [62]
2 years ago
14

HELPPPPPPPPP PLEASEEEEEE I NEEED HELPPPPPPPP BEGGINGGGG SOMEONE PLEASEEEEEE PLEASEEEEEEE HELPPPPPPPPPPPPPP PLEASEEEEEEEE​

Mathematics
1 answer:
sergeinik [125]2 years ago
5 0

Answer:

630 desks

Step-by-step explanation:

x=25

y=30

total desks = 25*24+30

total desks = 630

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What is the GCF of 88 and 66?
Vadim26 [7]

Answer:

the GCF would be 22 this is because that is 88 and 66 greatest common factor (gcf)

Step-by-step explanation:

have a good day!!

7 0
3 years ago
Read 2 more answers
Before a basketball game a referee noticed that the ball seemed under inflated. She dropped it from 6 feet and measured the firs
deff fn [24]

Answer: a) H = h( 0.5 )^n

b) H = 1.125inches

Step-by-step explanation:

Let H = height of the ball

n = number of time the ball bounces

h = initial height.

The exponential function to model the height of the ball will be:

H = h( 1 - 0.5)^n

H = h( 0.5 )^n

It's minus because the height of the ball is decreasing.

h = 36 inches

n = 5

H = 36( 1 - 0.5 ) ^5

H = 36( 0.5 )^5

H = 36 × 0.03125

H = 1.125inches

7 0
3 years ago
a box of cereal states that there are 72 calories in a 3/4 cup serving. What is the unit rate for calories per cup? how many cal
Leona [35]

Answer:

96 and 192 calories

Step-by-step explanation:

<u>Given</u>

  • 72 calories in a 3/4 cup

<u>Divide both by 3/4 to find the unit rate:</u>

  • 72:3/4 in 3/4:3/4
  • 96 calories in 1 cup

<u>Then multiply both by 2 to get the calories for 2 cups:</u>

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7 0
3 years ago
There are 80 seats in the small screen.
DanielleElmas [232]
One quarter of 80 is 20
7 0
2 years ago
If $10,500 is deposited in a compound interest account paying 2.99% interest annually, how much will be in the account after 5 y
algol [13]

\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$10500\\ r=rate\to 2.99\%\to \frac{2.99}{100}\dotfill &0.0299\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &5 \end{cases} \\\\\\ A=10500\left(1+\frac{0.0299}{1}\right)^{1\cdot 5}\implies A=10500(1.0299)^5\implies A\approx 12166.47

5 0
3 years ago
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