Answer:
![x=25](https://tex.z-dn.net/?f=x%3D25)
Step-by-step explanation:
we know that
In this problem
The value of x represent the radius of the circle
so
Applying the Pythagoras theorem in the right triangle of the figure, you can find the radius of the circle O
see the attached figure to better understand the problem
![x^{2} =20^{2}+15^{2}](https://tex.z-dn.net/?f=x%5E%7B2%7D%20%3D20%5E%7B2%7D%2B15%5E%7B2%7D)
![x^{2} =400+225](https://tex.z-dn.net/?f=x%5E%7B2%7D%20%3D400%2B225)
![x^{2} =625](https://tex.z-dn.net/?f=x%5E%7B2%7D%20%3D625)
square root both sides
![x=25](https://tex.z-dn.net/?f=x%3D25)
Step-by-step explanation:
![\frac{1}{1 + \sin( \alpha ) } \frac{1}{1 - \sin( \alpha ) } \\ \frac{1 - \sin( \alpha ) + 1 + \sin( \alpha ) }{(1 + \sin( \alpha ))(1 - \sin( \alpha )) } \\ = \frac{2}{1 - {sin}^{2} \alpha } \\ \frac{2}{ {cos}^{2} \alpha } = 2 \: {sec}^{2} \alpha](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B1%20%2B%20%20%5Csin%28%20%5Calpha%20%29%20%7D%20%20%5Cfrac%7B1%7D%7B1%20-%20%20%5Csin%28%20%5Calpha%20%29%20%7D%20%20%5C%5C%20%20%5Cfrac%7B1%20-%20%20%5Csin%28%20%5Calpha%20%29%20%2B%201%20%2B%20%20%5Csin%28%20%5Calpha%20%29%20%20%7D%7B%281%20%2B%20%20%5Csin%28%20%5Calpha%20%29%29%281%20-%20%20%5Csin%28%20%5Calpha%20%29%29%20%20%7D%20%20%5C%5C%20%20%3D%20%20%5Cfrac%7B2%7D%7B1%20-%20%20%7Bsin%7D%5E%7B2%7D%20%5Calpha%20%7D%20%20%5C%5C%20%20%5Cfrac%7B2%7D%7B%20%7Bcos%7D%5E%7B2%7D%20%5Calpha%20%20%7D%20%3D%202%20%20%5C%3A%20%20%7Bsec%7D%5E%7B2%7D%20%20%5Calpha%20)
Answer:
5x
Step-by-step explanation:
since opposite of negative is positive
THEYRE CORRESPONDING ANGLES :)